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Aleksandr [31]
2 years ago
15

What is the largest possible number of peopel at a party if no two of them have birthdays in the same month

Mathematics
1 answer:
lakkis [162]2 years ago
5 0

Answer:

12

Step-by-step explanation:

The answer is 12 because there are 12 different months in a year and also all the attendees must have birthdays in different months and not in the Same month. Hence 12 the largest possible number of attendees

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4.
Reptile [31]

Answer:

c.) 7.5

Step-by-step explanation:

There is a part-to-whole relationship here.

2 customers : 8 minutes= ? customers : 30 minutes

                                         <em>or...</em>

2/8=x/30

Cross multiply:

8x=60

Divided both sides by 8:

x=60/8=7.5

I hope this helps!

8 0
3 years ago
Solve the system using elimination.
NeX [460]

Answer:

This equation has no solution

Step-by-step explanation:

if the same equation equals 2 different numbers then therefore there is no solution.

6 0
1 year ago
Prove that the two circles shown below are similar. Circle A is shown with a center at 3, 4 and a radius of 5. Circle C is shown
MaRussiya [10]

Answer:

Is there a picture to go with it?

Step-by-step explanation:

8 0
2 years ago
1) (Modelo lineal de costo) Juan Chávez produce juguetes didácticos, para la fabricación de estos juguetes tiene costos fijos me
grandymaker [24]

Answer:

C = 2000 + 25 * X

$ 7000

Step-by-step explanation:

We have that the value of the total costs is equal to the fixed costs plus the variable costs.

As fixed costs we have $ 2000 and variable cost we have $ 25 for each unit, that is, the equation for total costs would be:

Let x be the number of toys, then:

C = 2000 + 25 * X

If there are 200 toys, the cost would be:

Replace x with 200:

C = 2000 + 25 * 200

C = 7000

In other words, the cost of producing 200 toys would be $ 7000.

7 0
3 years ago
(HURRY! I'M BEING TIMED)Write the partial fraction decomposition of the rational expression.
Aleonysh [2.5K]

Answer:

The partial fraction decomposition is \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}.

Step-by-step explanation:

Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.

To find the partial fraction decomposition of \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}:

First, the form of the partial fraction decomposition is

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{A}{x + 1}+\frac{B}{\left(x + 1\right)^{2}}+\frac{C}{x + 2}

Write the right-hand side as a single fraction:

                             \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B}{\left(x + 1\right)^{2} \left(x + 2\right)}

The denominators are equal, so we require the equality of the numerators:

             - 4 x^{2} + 13 x - 12=\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B

Expand the right-hand side:

           - 4 x^{2} + 13 x - 12=x^{2} A + x^{2} C + 3 x A + x B + 2 x C + 2 A + 2 B + C

The coefficients near the like terms should be equal, so the following system is obtained:

\begin{cases} A + C = -4\\3 A + B + 2 C = 13\\2 A + 2 B + C = -12 \end{cases}

Solving this system, we get that A=50, B=-29, C=-54.

Therefore,

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}

7 0
3 years ago
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