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4 years ago

Please help me!! Just help me solve

Mathematics

1 answer:

Kruka [31]4 years ago

4 0

The solution for the system of equations are:
$x = \frac{7}{5} \\ y = \frac{11}{5}$
Attached is the graph of lines y=3x-2 and y=-2x+5.

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A tissue box in the shape of a rectangular prism has a surface area of 158 square inches . The width is 5 inches and the height

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Answer:

A. 8.0 inches

you will have to use the formula A= 2(LW + LH + WL)

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3 years ago

Harper has $15.00 to spend at the grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers

Grace [21]

Since harper has only %15 that is the most she can spend, therefore we would have 15> or = 4.75b+3.5c. the best way to solve this would be to divide 15 by 4.75, then round down to the nearest whole number. if you do this, you get 3 bags of fruit.

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3 years ago

Read 2 more answers

Select the quadratic function that corresponds to each graph below

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C B A are the orders of the answers

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3 years ago

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(posting this for my friend) SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER

Pani-rosa [81]

Answer:

Step-by-step explanation:

the 90 degree angle is subtracted by 45 and the answer is.

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3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago