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vaieri [72.5K]
3 years ago
5

Please help me!! Just help me solve

Mathematics
1 answer:
Kruka [31]3 years ago
4 0
The solution for the system of equations are:
x =  \frac{7}{5} \\ y =  \frac{11}{5}
Attached is the graph of lines y=3x-2 and y=-2x+5.

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The quotient of a number and 5, less 10, is 3
sergejj [24]
Quotient is the result of division. Assign a variable to the unknown number. Let's make it x. Write the statement as an equation.
x/5 - 10 = 3

solve for x

x/5 - 10 = 3
x/5 = 3 + 10
x/5 = 13
x = 5 × 13
x = 65 

4 0
3 years ago
Where are all the math whizzes? I need your help, please! I will mark brainliest!
hjlf

Answer:

E

Step-by-step explanation:

A. x/yx * zy/yx = 2/x

B. x/y + y/z = (xz+y^2)/yz

C. x*z/z*x = 1

D. (x+y)/(y+z) = y(x+1)/y(1+z) = x+1/1+z

E. x/y / z/y = x/y * y/z = x/z

4 0
3 years ago
An equation of the perpendicular bisector of the line segment with end points (3,0) and (-3,0) is
Norma-Jean [14]

Answer:

x = 0

Step-by-step explanation:

Given

(x_1,y_1) = (3,0)

(x_2,y_2) = (-3,0)

Required

The equation of the perpendicular bisector.

First, calculate the midpoint of the given endpoints

(x,y) = 0.5(x_1 + x_2, y_1 + y_2)

(x,y) = 0.5(3-3, 0+ 0)

(x,y) = 0.5(0, 0)

Open bracket

(x,y) = (0.5*0, 0.5*0)

(x,y) = (0, 0)

Next, determine the slope of the given endpoints.

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{0 - 0}{-3- 3}

m = \frac{0}{-6}

m = 0

Next, calculate the slope of the perpendicular bisector.

When two lines are perpendicular, the relationship between them is:

m_2 = -\frac{1}{m_1}

In this case:

m = m_1 = 0

So:

m_2 = -\frac{1}{0}

m_2 = unde\ fined

Since the slope is unde\ fined, the equation is:

x = a

Where:

(x,y) = (a,b)

Recall that:

(x,y) = (0, 0)

So:

a = 0

Hence, the equation is:

x = 0

5 0
3 years ago
Lisa's car gets 18 miles per gallon of gasoline. how many miles can she drive on 60 gallons of gas?
nlexa [21]
60x18= 1080

1080 miles
4 0
3 years ago
Which shows a reflection of the triangle?
lora16 [44]
C, or the last photo, shows a reflection.
4 0
3 years ago
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