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vaieri [72.5K]
4 years ago
5

Please help me!! Just help me solve

Mathematics
1 answer:
Kruka [31]4 years ago
4 0
The solution for the system of equations are:
x =  \frac{7}{5} \\ y =  \frac{11}{5}
Attached is the graph of lines y=3x-2 and y=-2x+5.

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Help!! It should be easy it’s 7th grade math
Katen [24]

Answer:

The watermelon candies taste $0.13 more.

Step-by-step explanation:

First, in order to find out how much each candy costs per ounce, you have to take the cost and divide it by the number of ounces. 3.48 divided by 12 is 0.29, so the watermelon candies cost $0.29 per ounce. 1.38 divided by 8 is 0.16, so the chewy chocolates cost $0.16 per ounce. In order to find how much more the watermelon candies cost, we have to subtract the cost of the watermelon candies by the cost of the chocolate candies. 0.29-0.16=0.13, so the watermelon candies cost $0.13 more than the chocolate candies.

7 0
3 years ago
M is the midpoint of DE. If MD = 4x - 6 and ME = 3x + 2, find the length of DE.
bekas [8.4K]
The length of the de uwb
5 0
3 years ago
Part of a W-2 form is shown.
Fed [463]
I don’t see the form
6 0
4 years ago
Read 2 more answers
3. (2, 4), (-2, 2), (2, ο)<br> Is this set of numbers a function or not a function?
WINSTONCH [101]

Answer:

not a function

Step-by-step explanation:

This is not a function

The input 2 goes to two different outputs

2 goes to the output of 4 and the output of 0

This makes it a relation and not a function

6 0
3 years ago
A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure anti
Brums [2.3K]

\bf \begin{array}{lcccl} &\stackrel{solution}{gallons}&\stackrel{\textit{\% of }}{antifreeze}&\stackrel{\textit{gallons of }}{antifreeze}\\ \cline{2-4}&\\ \textit{1st brand}&x&0.65&0.65x\\ \textit{2nd brand}&y&0.90&0.9y\\ \cline{2-4}&\\ mixture&40&0.8&32 \end{array}~\hfill \to \begin{cases} x+y&=40\\ \boxed{x}=40-y\\ \cline{1-2} 0.65x+0.9y&=32 \end{cases} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{substituting in the 2nd equation}}{0.65\left( \boxed{40-y} \right)+0.9y=32}\implies 26-0.65y+0.9y=32 \\\\\\ 26+0.25y=32\implies 0.25y=6\implies y=\cfrac{6}{0.25}\implies \blacktriangleright y=24 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that}}{x=40-y\implies }x=40-24\implies \blacktriangleright x=16 \blacktriangleleft

7 0
3 years ago
Read 2 more answers
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