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3 years ago

5

Please help me!! Just help me solve

1 answer:

Kruka [31]3 years ago

4 0

The solution for the system of equations are:
$x = \frac{7}{5} \\ y = \frac{11}{5}$
Attached is the graph of lines y=3x-2 and y=-2x+5.

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The quotient of a number and 5, less 10, is 3

sergejj [24]

Quotient is the result of division. Assign a variable to the unknown number. Let's make it x. Write the statement as an equation.
x/5 - 10 = 3

solve for x

x/5 - 10 = 3
x/5 = 3 + 10
x/5 = 13
x = 5 × 13
x = 65

4 0

3 years ago

Where are all the math whizzes? I need your help, please! I will mark brainliest!

hjlf

Answer:

E

Step-by-step explanation:

A. x/yx * zy/yx = 2/x

B. x/y + y/z = (xz+y^2)/yz

C. x*z/z*x = 1

D. (x+y)/(y+z) = y(x+1)/y(1+z) = x+1/1+z

E. x/y / z/y = x/y * y/z = x/z

4 0

3 years ago

An equation of the perpendicular bisector of the line segment with end points (3,0) and (-3,0) is

Norma-Jean [14]

Answer:

$x = 0$

Step-by-step explanation:

Given

$(x_1,y_1) = (3,0)$

$(x_2,y_2) = (-3,0)$

Required

The equation of the perpendicular bisector.

First, calculate the midpoint of the given endpoints

$(x,y) = 0.5(x_1 + x_2, y_1 + y_2)$

$(x,y) = 0.5(3-3, 0+ 0)$

$(x,y) = 0.5(0, 0)$

Open bracket

$(x,y) = (0.5*0, 0.5*0)$

$(x,y) = (0, 0)$

Next, determine the slope of the given endpoints.

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{0 - 0}{-3- 3}$

$m = \frac{0}{-6}$

$m = 0$

Next, calculate the slope of the perpendicular bisector.

When two lines are perpendicular, the relationship between them is:

$m_2 = -\frac{1}{m_1}$

In this case:

$m = m_1 = 0$

So:

$m_2 = -\frac{1}{0}$

$m_2 = unde\ fined$

Since the slope is $unde\ fined$ , the equation is:

$x = a$

Where:

$(x,y) = (a,b)$

Recall that:

$(x,y) = (0, 0)$

So:

$a = 0$

Hence, the equation is:

$x = 0$

5 0

3 years ago

Lisa's car gets 18 miles per gallon of gasoline. how many miles can she drive on 60 gallons of gas?

nlexa [21]

60x18= 1080

1080 miles

4 0

3 years ago

Which shows a reflection of the triangle?

lora16 [44]

C, or the last photo, shows a reflection.

4 0

3 years ago

Read 2 more answers