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Rina8888 [55]
3 years ago
14

A bag has 9 marbles: 4 are green, 2 are red, and 3 are blue. Melissa chooses a marble at random, and without putting it back, ch

ooses another one at random. What is the probability that the first marble is blue and the second is green? Write your answer as a fraction in simplest form.
Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

Answer: pr (blue) = 1/3 or 0.33

Pr(green without replacement) = 1/2 = 0.5

Step-by-step explanation:

Probability = number of possible outcomes/ number of total outcomes

Total number of outcomes is the sum of all the marbles, given as 9

Pr ( first marble blue) = no of blue marbles/ total number of marbles

= 3/9 = 1/3 or 0.333

Second marble is chosen without replacement- this means that the total outcome has reduced by 1, total number of marbles has reduced to 8 because there was no replacement.

Pr (second marble is green) = number of green marble/ total number of marbles without replacing the first marble

= 4/8 = 1/2 = 0.5

I hope this helps.

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Answer:

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.

Step-by-step explanation:

1) Data given and notation  

n=420095 represent the random sample taken

X=135 represent the subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

\hat p=\frac{135}{420095}=0.0003214 estimated proportion of subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

p_o=0.00034 is the value that we want to test

\alpha=0.005 represent the significance level

Confidence=99.5% or 0.995

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the brain or nervous system at a rate that is different from the rate of 0.0340% :  

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Alternative hypothesis:p \neq 0.00034  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

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The significance level provided \alpha=0.005. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

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So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.  

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