Answer:
44, 46, and 48
Step-by-step explanation:
add them and you should get 138.
Answer:
The other zeros are -2 and 3.
Step-by-step explanation:
As 1 is a zero then (x - 1) is a factor so we divide:
x - 1 )x^3-2x^2-5x+6(x^2-x-6
x^3-x^2
-x^2-5x
-x^2+x
-6x+6
-6x+6
...........
x^2 - x - 6 = 0
(x - 3)(x + 2)
x = -2, 3.
Answer: x = (-3,3), y = (-5,5)
Step-by-step explanation:
Add both of the equations together, for
. Now we can divide both sides by 3, getting
. we subtract the first equation from our equation we just got, getting
y= (5,-5). once we plug that in, we get
,
x = (-3,3)
Answer:
The number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean is:

The margin of error for this interval is:

The information provided is:
<em>σ</em> = $569
MOE = $140
Confidence level = 95%
<em>α</em> = 5%
Compute the critical value of <em>z</em> for <em>α</em> = 5% as follows:

*Use a <em>z</em>-table.
Compute the sample size required as follows:
![n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 569}{140}]^{2}\\\\=63.457156\\\\\approx 64](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%20569%7D%7B140%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D63.457156%5C%5C%5C%5C%5Capprox%2064)
Thus, the number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.