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AURORKA [14]
2 years ago
12

Solve each inequality. (x – 3)(x - 2)^2 > 0

Mathematics
1 answer:
Rudiy272 years ago
6 0

Answer:

Write it like x>3 instead.

Work:

Solve for  x  by simplifying both sides of the inequality, then isolating the variable.

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Does the fraction 1/2 make the equation +6/6=3/2 true?
dolphi86 [110]

Answer:

Yes

Step-by-step explanation:

1/2 + 6/6

= (1*3)/(2*3) + 6/6

= 3/6 + 6/6

= 9/6

= 3/2

So the fraction 1/2 make the equation true.

7 0
2 years ago
Read 2 more answers
HELP ME PLEASEEEEEEEE ASAPPPP !!
OLEGan [10]

Answer:

C and D

Step-by-step explanation:

Mathematically, a unit circle is one in which the value of the radius is 1 unit

Generally, for a unit circle we have it that;

r^2 = x^2 + y^2

where (x,y) represents the coordinates of a point on the unit circle

But from above, r = 1

Thus:

x^2 + y^2 = 1

Looking at option C, by squaring each coordinate, we have

(6/7)^2 = 36/49 and the second as 13/49

by adding both, we have

36/49 + 13/49 = 49/49 = 1

Thus, we have this as a coordinate on the unit circle

For the last option;

(5/13)^2 = 25/169 and (12/13)^2 = 144/169

Adding both, we have;

25/169 + 144/169 = 169/169 = 1

So this is also a point on the unit circle

5 0
3 years ago
2.34 cm are equal to 23.4 millimeters
Shalnov [3]
Yes this is true since to covert cm to mm we have to multiply it by 10
4 0
3 years ago
Read 2 more answers
It can be considered as assumed mean​
Alexxx [7]

Answer:

what you on about?

Step-by-step explanation:

5 0
2 years ago
If a certain canon is fired from a height of 8.9 m above the ground, at a certain angle, the height of the Campbell above the gr
qwelly [4]

Answer:

T=5.9235 seconds

Step-by-step explanation:

H(T)= -4.9T^2+27.52T+8.9.

The time it takes for the cannonball to strike the ground is the point at which H(T)=0

H(T)= -4.9T^2+27.52T+8.9.=0

-4.9T^2+27.52T+8.9=0

This is a quadratic equation and since we have a bunch of decimals we use the quadratic formula:

x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}

a=-4,9, b=27.52, c=8.9

T=\dfrac{-27.52\pm\sqrt{(-27.52)^2-(4*-4.9*8.9)} }{2*-4.9}\\=\dfrac{-27.52\pm\sqrt{757.3504-(-174.44)} }{-9.8}\\=\dfrac{-27.52\pm\sqrt{931.7904} }{-9.8}\\=\dfrac{-27.52\pm30.53 }{-9.8}\\T=-0.3071 \:or\:  5.9235\\T=5.9235 seconds

It takes 5.9235 seconds for the cannonball to strike the ground.

4 0
2 years ago
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