What operation will you perform to solve the expression 4 × 16^3 + 10?

A fair coin is tossed 5 times. What is the probability of obtaining exactly 3 heads.

vichka [17]

Coin tossed : 5 times
Heads and 3 times

Probability: 3:5

3 0

3 years ago

Ryan has two jobs. He earns $9 per hour for x hours babysitting his cousins and he earns $18 per hour for y hours working at the

Volgvan

Answer:

Umm I don't think you wrote out the whole question...

Step-by-step explanation:

$18 nine hours, $9 one hour = $177

$18 eight hours, $9 two hours = $162

$18 seven hours, $9 three hours = $153

$18 six hours, $9 four hours = $144

$18 five hours, $9 five hours = $135

$18 four hours, $9 six hours = $126

$18 three hours, $9 seven hours = $117

$18 two hours, $9 eight hours = $108

$18 one hour, $9 nine hours = $99

5 0

3 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

A red ribbon 11 meters long is 5 times as long as a blue ribbon. How long is the blue ribbon?

aev [14]

Red ribbon

=Blue ribbon ×5

=11 m

So, changes the times symbol into divide

11m ÷ 5

=2.2m

Check!

Red ribbon=Blue ribbon × 5

11m=Blue ribbon × 5

11m÷5=Blue ribbon

2.2m=Blue ribbon

Blue ribbon=2.2m

Answers

2.2m

5 0

3 years ago

The area of a triangle whose height is 1 more than 6 times its base is 13 square feet. If the base of the triangle is x feet, wh

brilliants [131]

The correct answer is choice C. Here is the reason. If you substitute the information into the formula this is what it would be:
A = bh/2
13 = x (6x + 1)/2
13 = (6x^2 + x)/2
26 = 6x^2 + x
0 = 6x^2 + x - 26

4 0

3 years ago