Im there so what math problem
The given equation is ⇒⇒⇒ 2y - 4x = 6
∴ 2y = 4x + 6 ⇒ divide all the equation over 2
∴ y = 2x + 3 and it can be written as ⇒⇒⇒ y - 2x = 3
The last equation represents a straight line with a slope = 2 and y-intercept = 3
To construct a system of equations with definitely many solutions and the equation ( 2y-4x=6 ) is one of the equations, the other equation must have the same slope and the same y-intercept.
so, the general solution of the other equation is ⇒ a ( y - 2x ) = 3a
Where a is constant and belongs to R ( All real numbers )
The system of equations which has definitely many solutions is consisting of <u>Coincident lines.</u>
Its pretty simple
9x-7y = 22
x + 3y = -24
(9x-7y = 22)
-9(x + 3y = -24)
= -9x -27y = 216
+ 9x-7y = 22
= -34y = 238
= / -34 = 238/-34
y = -7
now plug -7 in one of the equation
x + 3(-7) = -24
x -21 = -24
+21. +21
x = -3
so answer is x = -3 and y = -7
I believe that the answer is 25
Answer:
the answer is D
Step-by-step explanation:
I don't know how to explain it very well but the line starts at 2 then ends at 8
