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Luden [163]
3 years ago
13

HELPP ME PLZ WILLING TO SEND MONEY! It’s urgent

Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer:

Devon needs to add 60 mL of 5% acid solution and 30 mL of 20% acid solution

Step-by-step explanation:

It knows acid and water concentration for every solution. 2 equations are proposed because there are two unknowns. V1= volume 5%acid and V2 =volume 20% acid

Acid V1(0.05)+V2(0.2)=90mL(0.1)

Water V1(0.95)+V2(0.8)=90mL(0.9)

Clearing V1 from acid equation having to: V1=180-4V2

Replacing V1 in the water equation having to: (180-4V2)(095)+V2(0.8)=81

Clearing V2 = 30mL

Replacing in water equation V1(0.05)+30(0.2)=9 So, V1=60mL

ExtremeBDS [4]3 years ago
7 0

Answer:

I think it would be 5 and 5 of each solution

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The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
Use a model to divide. 1 ÷ 1/5
arlik [135]
This is the answer to the question

4 0
3 years ago
What is the value of y in the equation 4x +3 y= 23 when x=2 , x=6
balandron [24]

Answer:

5, -⅓

Step-by-step explanation:

x = 2:

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3y = 23 - 4(6)

3y = -1

y = -⅓

8 0
2 years ago
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Step-by-step explanation:

x+5=36

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2 years ago
Which equation has no solution?
steposvetlana [31]

Answer:

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Step-by-step explanation:

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