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3 years ago

Evaluate y^0. Please show working out. Thank you

Mathematics

1 answer:

jonny [76]3 years ago

7 0

So what would happen is that y is always the same, so if y is 2, then it will always be 2, however x does change. this is called a zero or no slope. Happy Valentines!

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Carla can choose two of her three pairs of sneakers to take to a track meet. If the pairs of sneakers are called A, B, and C, wh

iren2701 [21]

Answer:

s= {AB,AC,BC} edge. 2020

Step-by-step explanation:

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3 0

3 years ago

45 miles per hour into feet per second please show work I am hopless :(

Pavel [41]

There are 5280 feet in a mile
45 * 5280 = 237600
there are 3600 seconds in an hour (60 minutes time 60 seconds)
so we have 237600 feet in 3600 seconds
237600 / 3600 = 66 feet per second.

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3 years ago

4 yd 8 in + 6 yd 6 in=?

spin [16.1K]

Answer:

10 yd 15 in, or 10.33 3 in.

If one foot is .33 repeating of a yard, then

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3 years ago

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$