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Naya [18.7K]
3 years ago
9

F(x) = (1/4)^x. for x = -3

Mathematics
2 answers:
Trava [24]3 years ago
7 0
Plug in -3 for x into the equation.

(1/4)^-3

And solve

(1/4)^-3 = 64
Fantom [35]3 years ago
6 0
When an exponent is a negative number, it means that the term will be converted into a fraction, with 1 being the numerator, and the entire term being the denominator.

Rewrite the term:

F(-3) = \frac{1}{4}^{-3}

\frac{1}{\frac{1}{4}^3}

Solve the term in the denominator:

\frac{1}{4}^3 = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = \frac{1}{64}

\frac{1}{\frac{1}{4}^3} = \frac{1}{\frac{1}{64}}

There is a fraction within a fraction. In this case, a fraction is the denominator of another fraction. We can multiply out the denominator of the fraction and leave out its numerator to become the denominator of the bigger fraction:

\frac{1}{\frac{1}{64}} \times \frac{64}{64} = \frac{64}{1} = \boxed{64}

f(-3) will equal 64.
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5 0
3 years ago
A physical education department wanted a single test of upper body strength that was easy to administer. Dips on the parallel ba
Gennadij [26K]

Answer:

24.23 ; 13.47 ; 0.782 ; p value < 0.00001 ;7.45

Step-by-step explanation:

Given that :

ΣX = 3,416, ΣY = 1,899, SDX = 8.84, SDY = 4.70, ΣZXZY = 109.416

Sample size, N = 141

Mean of X:

£X / N = 3416 / 141 = 24.23

Mean of Y:

£Y / N = 1899 / 141 = 13.47

B.) Correlation between the 2 variables :

£ZXZY / N - 1

= 109.416 / 140

= 0.782

C.)

Level of significance and p value :

T = [Rsqrt(n-2)] ÷ sqrt(1 - R²)

T = [0.782 * sqrt(139)] ÷ sqrt(1-0.782^2)

T = 14.79

P value from Tscore calculator

Df = 141 - 2 = 139 ; α = 0.05

Pvalue = 0.00001

Pvalue < α ; Hence, a significant positive relationship exists.

To obtain regression model :

Slope = £ZXZY / SDX²

m = 109.416 / 8.84^2 = 1. 4

yintercept = meanY - slope*x

yintercept = 13.47 - 1.4*24.3

yintercept = - 20.55

Equation in slope intercept form:

y = mx + c

y = 1.4x - 20.55

For x = 20

y = 1.4(20) - 20.55

y = 7.45

5 0
3 years ago
Charlotte bought 16 songs for her MP3 player. Three-fourths of the songs are classical songs. How many of the songs are classica
spayn [35]
I think 8 are classical songs
3 0
3 years ago
Read 2 more answers
Ryan flew from Wiley Post to Ponca City and back. Ryan maintained an average rate of 450 mph going to Ponca City and an average
Reil [10]
The answer is B, and here's why.  Set up a table for "there" and "back" and use the distance = rate * time formula, like this:
               d             r            t
there       d           450         t
back        d           400        1-t

Let me explain this table to you.  The distance is d, we don't know what it is, that's what we are actually looking for.  We only know that if we go somewhere from point A to point B, then back again to point A, the distance there is the same as the distance back.  Hence, the d in both spaces.  There he flew 450 mph, back he flew 400 mph.  If the total distance was 1 hour, he flew an unknown time there and one hour minus that unknown time back.  For example, if he flew for 20 minutes there, one hour minus 20 minutes means that he flew 60 minutes - 20 minutes = 40 minutes back.  See? Now, because the distance there = the distance back, we can set the rt in both equal to each other.  If d = rt there and d = rt back and the d's are the same, then we can set the rt's equal to each other.  450t = 400(1-t) and
450t = 400 - 400t and 850t = 400.  Solve for t to get t = .47058.  Now, t is time, not the distance and we are looking for distance. So multiply that t value by the rate (cuz d = r*t) to get that the distance one way is
d = 450(.470580 and d = 211. 76 or, rounded like you need, 212.
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3 years ago
In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons
GuDViN [60]

Answer:

SEE EXPLANATION

Step-by-step explanation:

In\:\triangle AOC \:\&\:\triangle BOD

AO \cong OB.... (given)

\angle AOC \cong\angle BOD

(vertical \: \angle s)

CO \cong OD.... (given)

\therefore \triangle AOC \:\cong\:\triangle BOD

(SAS \: postulate)

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

AC = BD

m\angle OAC = m\angle OBD

m\angle OCA = m\angle ODB

7 0
3 years ago
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