Question 14, Part (i)
Focus on quadrilateral ABCD. The interior angles add to 360 (this is true for any quadrilateral), so,
A+B+C+D = 360
A+90+C+90 = 360
A+C+180 = 360
A+C = 360-180
A+C = 180
Since angles A and C add to 180, this shows they are supplementary. This is the same as saying angles 2 and 3 are supplementary.
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Question 14, Part (ii)
Let
x = measure of angle 1
y = measure of angle 2
z = measure of angle 3
Back in part (i) above, we showed that y + z = 180
Note that angles 1 and 2 are adjacent to form a straight line, so we can say
x+y = 180
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We have the two equations x+y = 180 and y+z = 180 to form this system of equations

Which is really the same as this system

The 0s help align the y terms up. Subtracting straight down leads to the equation x-z = 0 and we can solve to get x = z. Therefore showing that angle 1 and angle 3 are congruent. We could also use the substitution rule to end up with x = z as well.
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The population proportion is 
The sample size is n = 563
Generally the population mean of the sampling distribution is mathematically represented as

Generally the standard deviation of the sampling distribution is mathematically evaluated as

=>
=>
Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

Here
is the sample proportion of persons with a college degree.
So
![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%28%5Cfrac%7B%5B%5B0.05%20-0.52%5D%5D-%200.52%7D%7B0.02106%7D%20%3C%20%5Cfrac%7B%5B%5C%5Ep%20-%20p%5D%20-%20p%7D%7B%5Csigma%20%7D%20%20%3C%20%5Cfrac%7B%5B%5B0.05%20-0.52%5D%5D%20%2B%200.52%7D%7B0.02106%7D%20%29)
Here
![\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))](https://tex.z-dn.net/?f=%5Cfrac%7B%5B%5C%5Ep%20-%20p%5D%20-%20p%7D%7B%5Csigma%20%7D%20%20%3D%20Z%20%28The%5C%20standardized%20%5C%20%20value%20%5C%20%20of%5C%20%20%28%5C%5E%20p%20-%20p%29%29)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%5B%5Cfrac%7B-0.47%20-%200.52%7D%7B0.02106%20%7D%20%20%3C%20%20Z%20%20%3C%20%5Cfrac%7B-0.47%20%2B%200.52%7D%7B0.02106%20%7D%5D)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%5B%20-2.37%20%3C%20%20Z%20%20%3C%202.37%20%5D)
=> 
From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is

and

So
=>
=>
=> 
14/175 x 100 = 8%
answer is A. 8 (first choice)
We have the following equation:
2 (x-3) ^ 2 + 10 = 82
We must clear x.
We pass the constant terms to one side of the equation:
2 (x-3) ^ 2 = 82 - 10
2 (x-3) ^ 2 = 72
(x-3) ^ 2 = 72/2
(x-3) ^ 2 = 36
Square root to both members:
x-3 = +/- root (36)
x-3 = +/- 6
The solutions are:
x1 = 6 + 3 = 9
x2 = -6 + 3 = -3
Answer:
x1 = 9
x2 = -3
Answer:
x=-2, y=-4. (-2, -4).
Step-by-step explanation:
2x-y=0
y=x-2
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2x-(x-2)=0
2x-x+2=0
x+2=0
x=0-2
x=-2
y=-2-2=-4