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marta [7]
3 years ago
8

Which matrix represents the system of equations shown below Plz help.. See picture

Mathematics
2 answers:
marusya05 [52]3 years ago
5 0

Answer:

Matrix D represents the given system of equation.

Step-by-step explanation:

We have been given system of equation:

3x+y=1

And -y=5

Coefficient of first equation will form first row and the constant on right hand side will comes in the side column  and second equation will form second row the constant on right hand side will comes in the side column

Hence, the matrix will be given by:

Matrix D represents the given system of equation.

Furkat [3]3 years ago
4 0
Basically

just put the coeficinets of each variable in the apropriate row

example
ax+by=c and
dx+ey=f

would go in like this
\left[\begin{array}{ccc}a&b&|c\\d&e&|f\end{array}\right]

so
3x+1=1 and
0x-1y=5

\left[\begin{array}{ccc}3&1&|1\\0&-1&|5\end{array}\right]

D is answer


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What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C
butalik [34]

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

{(2x - 3y)}^{10}

Compare this to

{(a + b)}^{n}

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

{x}^{5}  {y}^{5}

This implies that, r=5.

The terms in the expansion can be obtained using

T_{r+1}=nC_ra^{n-r}b^r

We substitute the given values to obtain;

T_{5+1}=10C_5(2x)^{10-5}(  - 3y)^5

T_{6}=10C_5(2x)^{5}(3y)^5

T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5}  {y}^{5}

Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

5 0
3 years ago
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I need to equation for the radius of a 400m running track I know the answer is 36.5 and I know the formula is =2<img src="https:
miskamm [114]
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6 0
3 years ago
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Verdich [7]

Answer:

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Step by Step:

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7 0
3 years ago
What is the solution to 3x+30+x=10+2x+5x+2?
solmaris [256]

Answer:

answer is x = 6

„„„„„„„„»»»»»»»»»»

I hope it helps you

:-))

4 0
3 years ago
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I need help with with problem please thanks!
liraira [26]
40 is the correct answer. Hope this helps :)
5 0
3 years ago
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