Answer:
4 meters per second
Step-by-step explanation:
200 ÷ 50 = 4
1. First, do 12 x 8 to work out the area of the rectangle, which is 96ft.
Then, to work out the area of a circle, you use the equation πr² to help you. You would multiply π by the radius², which is 16. Now you have just worked out the area of a circle, but not a semicircle, so you would have to divide your answer by two to get the area of this, which would be 25.13 (rounded to 2 d.p).
To get the area of the whole shape, you just have to add the two totals together.
25.13 + 96 = 121.13ft.
Remember to put the units there, or you can lose marks.
Try your best with the next questions! I have written the formulas for the other shapes to help you work out the answers.
Area of a square = Multiply sides together.
Area of rectangle = Multiply width by length.
Area of a circle = Multiply π by the radius².
Area of a semicircle = Multiply π by the radius², and the divide by two.
Area of a triangle = Multiply the base by the height, and then divide by two.
Really hope this helps!
Answer:
Amount of money share by Jess = £25.70
Another Amount of money share by Jess = £34.3
Step-by-step explanation:
Given:
Amount of money Jess have = £60
Sharing ratio = 3 : 4
Find:
Amount of money share by Jess
Computation:
Sharing amount = Shared ratio / Sum of ratio
Amount of money share by Jess = 60[3/(3+4)]
Amount of money share by Jess = 60[3/(7)]
Amount of money share by Jess = 180 / 7
Amount of money share by Jess = £25.70
Another Amount of money share by Jess = £60 - £25.70
Another Amount of money share by Jess = £34.3
Answer:
First, use the table above to start putting the answers into your memory. Then use the Math Trainer - Multiplication to train your memory, it is specially designed to help you memorize the tables. Use it a few times a day for about 5 minutes each, and you will learn your tables.
Let
. Then


and substituting these into the ODE gives



Let
, so that
. Then the ODE is linear in
, with

Multiply both sides by
, so that the left side can be condensed as the derivative of a product:

Integrating both sides and solving for
gives

Integrate again to solve for
:

and finally, solve for
by multiplying both sides by
:

already accounts for the
term in this solution, so the other independent solution is
.