All categories

2 years ago

I'm behind on hw and I'm going to fail if I don't get help.

Mathematics

1 answer:

Reil [10]2 years ago

6 0

Number two is A........hope this helps

You might be interested in

-5x-6. pls answer ill mark you brainliest

Artyom0805 [142]

Answer:

This is not an equation. So it's not possible to find the value of x..

7 0

2 years ago

Read 2 more answers

Have no idea how to do this-- Could someone show me how please.

motikmotik

Answer:

well E is (-7,-7) F is (-2,-3) G is (-1,-6)

Step-by-step explanation:

7 0

2 years ago

Can I get help on this math problem makes makes no sense

lana66690 [7]

(2,-1) The intersecting point is the point where the two lines meet.

5 0

3 years ago

Is 5:20 and 15:60 equivalent

kati45 [8]

Answer:

Yes! When simplifying 15:60 by dividing each side by 3, you get 5:20, which is the same as 5:20.

Step-by-step explanation:

Hope this helps <3

5 0

3 years ago

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref

hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

$\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}$

So the cost of laying pipe under water with this distance is

$800000\sqrt{(3 - d)^2 + 4}$

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

$800000\sqrt{(3 - d)^2 + 4} + 400000d$

We can find the minimum value of this by taking the 1st derivative and set it to 0

$800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0$

We can move the first term over to the right hand side and divide both sides by 400000

$1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}$

$\sqrt{(3 - d)^2 + 4} = 6 - 2d$

From here we can square up both sides

$(3 - d)^2 + 4 = (6 - 2d)^2$

$9 - 6d + d^2 + 4 = 36 - 24d + 4d^2$

$3d^2-18d+27 = 0$

$d^2 - 6d + 9 = 0$

$(d - 3)^2 = 0$

$d -3 = 0$

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0

3 years ago