<span>∇ · (|r| r)
=</span>|r| <span>∇ · ( r) + r </span><span>∇ · |r|
</span>
|r| =√x²+y²+z²
<span>∇ · ( r) =dr/dx +dr/dy+dr/dz= i+j+k
so
</span>∇ · (|r| r)
=<span>√x²+y²+z² (</span><span>i+j+k) + </span><span>(x i + y j + z k ) </span>∇ · |r|
∇ · |r|= 2(x+y+z)/<span>√x²+y²+z²
finally
</span>
∇ · (|r| r)
=<span> |r|</span><span> (i+j+k) + 2(xi+yj+zk)/</span><span> |r|=</span><span>|r| (i+j+k) + 2r/</span><span>|r|</span>
Ok so a∈{-3,-1,0}. then just {-3*-1,-1*-1,0*-1} which comes to {3,1,0}
Answer:
7a
Step-by-step explanation:
We don't actually know the variable A and we don't have a final product to help us solve it, so the best we can do is make 7 a coefficient to the variable A, making the answer 7a.
Answer:
Step-by-step explanation:
Hello!
We can factor this by grouping. We have to find two numbers that add up to -13 but multiply to 8 * 5 .
The two numbers that work are -8 and -5. Expand -13n to -8n and -5n.
<h3>Factor by Grouping</h3>
The factored expression is .
