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Degger [83]
3 years ago
6

)) Irene made 4 stacks of wooden blocks. The first stack was 4 blocks tall. The second

Mathematics
2 answers:
Romashka [77]3 years ago
6 0

Answer:

I am pretty sure the answer is 30 blocks :)

4 + 11 + 6 + 9 = 30 blocks

nordsb [41]3 years ago
5 0

Answer:

Step-by-step explanation:

If we know the first set of them is 4 blocks tall and the second set is 7 blocks taller.we add 4 plus 7=11 then the third set was 9 blocks shorter so we take away 11-9=2 and then last stack was 3 blocks taller which 2+3=5 so then u add all the answers up like this 4+11+2+5=22 the answer is 22 hope that help.!

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Put these in order starting from the smallest<br> 6^2 3^4 2^9<br> 5^3
Levart [38]

Answer:

6^2, 3^4, 5^3, and 2^9

Step-by-step explanation:

6^2= 36

3^4= 81

5^3= 125

2^9= 512

4 0
3 years ago
The perimeter of a rectangular pool is 306m. If the length of the pool is 87m, what is its width?
s344n2d4d5 [400]

Answer: the width is 66

Step-by-step explanation: see if 87m  is the width then you add it twice  it equals 174 then you subtract it from 306m which equals 132 but since theres two sides you divide it to get 66                Hope this help happy Easter!!  c:

4 0
3 years ago
The work of a student to solve a set of equations is shown below: m=8+2n; 4m=4+4n. Solve by elimination
nadya68 [22]

Answer:

Step-by-step explanation:

4(8+2n) = 4 + 4n

32 + 8n = 4+4n

4n = -28

n = -7

4 0
2 years ago
In parallelogram KLMN, NL=15. Identify NP. HELP PLEASE!!
adelina 88 [10]

Answer:

B

Step-by-step explanation:

Fact: The diagonals of a parallelogram bisect each other. If NL= 15 the NP = 1/2 NL

1/2 NL = 15/2 = 7.5.

NP = 7.5

Answer: NP = 7.5   B

7 0
3 years ago
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
2 years ago
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