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3 years ago

A quadrilateral has no pairs of parallel sides.what two shapes could be it

Mathematics

2 answers:

Basile [38]3 years ago

8 0

Answer:

All trapezoids are quadrilaterals.

Step-by-step explanation:

Incorrect. Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. A trapezoid can never be a parallelogram. The correct answer is that all trapezoids are quadrilaterals.

saul85 [17]3 years ago

7 0

Answer:

i need help it is the wrong answer

Step-by-step explanation:

All trapezoids are quadrilaterals.

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Cosx=4/5 what is sin2x cos2x and tan2x

earnstyle [38]

Answer:

-24/5

Step-by-step explanation:

The solution to the problem is as follows:

cscx < 0 means 1/sinx < 0, or sinx < 0.

sinx = -3/5 because you're dealing with a 3-4-5 triangle, and we established

sinx is negative.

sin2x = 2sinxcosx = 2*-3/5*4/5 = -24/25

cos(2x) = cos^2(x) - sin^2(x) = 16/25 - 9/25 = 5/25 = 1/5

tan2x = sin2x / cos2x = -24/5

4 0

2 years ago

PLEASE HELP ME ASAP!!!!!! ty :)

Drupady [299]

Answer:

B should be the answer but it could but C

3 0

2 years ago

Which of the following is more than 0.35 but less than 0.41

Hoochie [10]

Its B because 3/10ths is a little bit more than 0.35, but way less than 0.41

6 0

2 years ago

Read 2 more answers

Please help.............

natta225 [31]

Answer:

...........

2(x + 2) + 2x = 20

6 0

3 years ago

Read 2 more answers

(3ab+2c)^3 what is the answer

svet-max [94.6K]

Answer:

$=27a^3b^3+54a^2b^2c+36abc^2+8c^3$

Step-by-step explanation:

$(3ab+2c)^3$

$=(3ab+2c)$ × $(3ab+2c)$ ×

$=(3ab+2c)(9a^2b^2+12abc+4c^2)$

$=(3ab)(9a^2b^2)+(3ab)(12abc)+(3ab)(4c^2)+(2c)(9a^2b^2)+(2c)(12abc)+(2c)(4c^2)$

$=27a^3b^3+36a^2b^2c+12abc^2+18a^2b^2c+24abc^2+8c^3$

$=27a^3b^3+54a^2b^2c+36abc^2+8c^3$

hope this helps....

5 0

2 years ago