Answer:
The answer is 69.3 ms
Explanation:
if 1 MiB = 0.008388608 Gb
then 3 MiB = 3 x 0.008388608 = 0.025165824 Gb.
since the bandwidth is equally shared amongst two users, each user gets equal share of the bandwidth which is Total Bandwidth/Number of Users.(
The bandwidth for each user = 30.8/2 = 15.4 Gbps.
The time taken for the message to reach from host A to host B = 0.025165824/15.4 s = 0.00163414441 which is = 1.63 ms.
The link connection requires a setup time of 67.7 ms
Therefore, the net time required is = 67.7 ms +1.63 ms = 69.3 ms.
Answer:
when you call yourself fat or ugly......but that was my answer but pls dont ever be negative abt yalls selfs i love yall the way u are and if u eva wanna talk ill do it in the comments
Explanation:
Answer:
systematic sampling method
Explanation:
Based on the information provided within the question it can be said that in this scenario the method that was used was a systematic sampling method. This method focuses on selecting elements from a ordered sampling frame, which in this case refers to every 8th chip starting from the 3rd. This method repeats once the end of the list or process is reached which is 140 chips in this scenario.
Its a gear that is not turned manually and it can spin faster and longer than a manual gear.
What section is it? I did the same thing a bit ago on edhesive
