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shepuryov [24]
3 years ago
7

The length of a rectangle is 5 inches less than twice its width. The perimeter of the rectangle is 26 inches. What is the width

of the rectangle?​
Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0

Answer:

w= 6

Step-by-step explanation:

I just started by making an educated guess using the values already given. Then I inserted that into the problem to see if it worked.

L= 2w - 5

I used 6 as a random, educated guess for the value of w.

L = 2(6) - 5

L = 12-5

L = 7

Then, multiply L by 2 to account for both side lengths of the rectangle.

7(2)= 14

Subtract that value from the total perimeter to find what the width must equal.

26 - 14 = 12

Divide that answer by 2 since there are two sides for width.

12/2 = 6

I know this was kind of long, but I hope it helps! :)

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Please help with my math i took a picture of it
Fynjy0 [20]

Answer:

40°

Step-by-step explanation:

Supplementary angles add up to 180°.  Complementary angles add up to 90°.

m∠1 + m∠2 = 180°

115° + m∠2 = 180°

m∠2 = 65°

m∠2 + m∠3 = 90°

65° + m∠3 = 90°

m∠3 = 25°

m∠2 − m∠3 = 65° − 25° = 40°

6 0
3 years ago
3x+6/x^2-x-6+2x/x^2+x-12
Tanzania [10]
\dfrac{3x+6}{x^2-x-6} +  \dfrac{2x}{x^2+x-12}

= \dfrac{3(x+2)}{(x + 2)(x - 3)} +  \dfrac{2x}{ (x - 3)(x + 4)}

= \dfrac{3}{(x - 3)} +  \dfrac{2x}{ (x -3)(x + 4)}

= \dfrac{3(x+4)}{(x - 3)(x + 4)} +  \dfrac{2x}{ (x -3 )(x + 4)}

= \dfrac{3(x+4) + 2x }{(x - 3)(x + 4)}

= \dfrac{3x+12 + 2x }{(x - 3)(x + 4)}

= \dfrac{5x+12}{(x - 3)(x + 4)}



6 0
3 years ago
−8x+6−2=−12<br> what is x?
zubka84 [21]

Answer: x=2

Step-by-step explanation:

have a good day! :)

plz give me brainliest

4 0
3 years ago
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