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Lena [83]
3 years ago
10

Will award brainliest if answered within 10 minutes!

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
6 0
The answer would be:
y=-\frac{2}{1}x-4

Hope this helps
uysha [10]3 years ago
4 0
The answer is y=2x-4
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Whats 34 divided by 40?
Drupady [299]

34/40 = 17/20 in fraction form

& 0.85 in decimal form

5 0
2 years ago
Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

P(1):\ 1 = \dfrac{1\cdot 2}{2}=1

So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

4 0
3 years ago
10
Natasha2012 [34]

Answer:

x= -2

Step-by-step explanation:

Rational Function can be expressed as:

\displaystyle \large{y =  \frac{a}{p(x - b)}  + q}

Where b is our horizontal shift and q is our vertical shift.

For asymptotes, there are two types which are vertical and horizontal.

Vertical Asymtote is the value of -b itself or x = -b.

Therefore, from the functio:

\displaystyle   \large{y =  \frac{10}{x + 2} }

Our vertical asymtote is x = -2

6 0
2 years ago
A jet is flying 7 miles above the ground. The pilot spots an airport as shown below. What is the distance from the plane to the
Fynjy0 [20]
It's hard to help if you can't provide everything with the question
8 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
BartSMP [9]

Answer:

d = √5 ≈ 2.24

Step-by-step explanation:

B is located at (1, 3) and B' is located at (3, 4)

Distance formula:

[tex] d = \sqrt{(xB' - xB)^2 + (yB' - yB)^2}[\tex]

replacing with the coordinates of the points:

[tex] d = \sqrt{(3 - 1)^2 + (4 - 3)^2}[\tex]

[tex] d = \sqrt{4 + 1}[\tex]

d = √5 ≈ 2.24

6 0
2 years ago
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