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3 years ago

Please Answer ASAP!

Mathematics

1 answer:

Nikitich [7]3 years ago

4 0

Step-by-step explanation:

-13 - 23 = -13 + (-23)

= -36

-13 - (-23) = -13 + 23

= 10

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Write the equation in slope intercept form.Then graph the line for 2x+y=4

soldier1979 [14.2K]

Answer:

y = -2x + 4

Step-by-step explanation:

slope intercept form: y = mx + b

2x + y = 4

Subtract 2x on both sides.

y = -2x + 4

To graph the line, you would start at (0, 4) and go up 2 and left 1 to (6, -1) and then draw a line through the points.

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4 years ago

The slope of the line passing through the points (2,3) and (4, y) is

umka2103 [35]

Answer:

Step-by-step explanation:

y2-y1 y-3 =3 what -3 =3? 6 :)

x2-x1 4-2 = 2

slope is 3/2

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4 years ago

What is the vertex of the function?

egoroff_w [7]

<h2>Explanation:</h2><h2></h2>

Here you haven't provided any function, so I'll assume this one:

$f(x)=3x^2-18x+33$

This is a quadratic function whose graph represents a parabola. Any parabola has its vertex at the point:

$V(x,y) \\ \\ \\ x=-\frac{b}{2a} \\ \\ y=f(-\frac{b}{2a}) \\ \\ \\ where: \\ \\ \\ f(x)=ax^2+bx+c \\ \\ \\ So: \\ \\ a=3 \\ \\ b=-18 \\ \\ c=33$

Therefore:

$x=-\frac{(-18)}{2(3)}=3 \\ \\ f(3)=3(3)^2-18(3)+33=27-54+33=6$

Therefore, the vertex is:

$\boxed{V(3,6)}$

6 0

4 years ago

What is the equivalent expression of 9+ a J plus 6J -1+ 2K

Salsk061 [2.6K]

Answer:

1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111

Step-by-step explanation:

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3 years ago

please help! functions and relations. f(x)= square root of x-4. find the inverse of f(x) and it’s domain.

likoan [24]

ANSWER:

$\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4$

STEP-BY-STEP EXPLANATION:

We have the following equation:

$f(x)=\sqrt{x}-4$

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

$\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\ \\ \sqrt{f^{-1}(x)}=x+4 \\ \\ f^{-1}(x)=(x+4)^2 \end{gathered}$

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

$\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4$

4 0

1 year ago