Answer:
±
,
Step-by-step explanation:
See the attached image
This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: that correspond to the force of resistance on the mass by the action of the spring and that is an external force with unknown direction (that does not specify in the enounce).
For determinate we can use Hooke's Law given by the formula where correspond to the elastic constant of the spring and correspond to the relative displacement of the mass-spring system with respect of his rest state.
We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...
Now we apply Newton's 2nd Law and obtaint that...
± =
Finally... ±
We know from the problem that there's not initial displacement and initial velocity, so... and
Finally the Initial Value Problem that models the situation describe by the problem is
Answer:
The volume of the cylinder is 9.42ft³
Step-by-step explanation:
radius = half of diameter
r = 2ft /2 = 1ft
To calculate the volume of a cylinder we have to use the following formula:
v = volume
h = height = 3ft
π = 3.14
r = radius = 1ft
v = (π * r²) * h
we replace with the known values
v = (3.14 * (1ft)²) * 3ft
v = (3.14 * 1ft²) * 3ft
v = 3.14ft² * 3ft
v = 9.42ft³
The volume of the cylinder is 9.42ft³
Answer:
g(x) = - x² - x + 12
Step-by-step explanation:
Given
g(x) = (- x - 4)(x - 3)
Each term in the second factor is multiplied by each term in the first factor, that is
- x(x - 3) - 4(x - 3) ← distribute both parenthesis
= - x² + 3x - 4x + 12 ← collect like terms
= - x² - x + 12 ← in standard form
Answer:
Multiple Answers
Step-by-step explanation:
- It is algebraically defined (that is, there is an equation you can use to calculate its value).
The mean is the average of our numbers, it is easy to calculate. The formule we use to calcule the mean is:
mean =
Where N is the number of values we have in our sample.
(We divide the sum of our values by the number of data we have in our sample).
- It is easily influenced by extreme scores.
If we have extreme scores in our sample our mean could be affected by them. To avoid this we can adjust our sample. We can do this by eliminate the values that are in the extreme of our ordened data (we can just avoid the 10% of the largest data and the 10% of the smallest data in our sample) the mean of the rest of the data we have is the adjusted mean.
where is your triangle mate??
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