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xenn [34]
3 years ago
5

What are like terms?

Mathematics
1 answer:
Tanya [424]3 years ago
4 0
Like terms are when you have 2 of the same coefficent disregarding the amount of numbers. you can add or subtract them to simplify in other words.
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18 less than the product of 42 and x write as an algebraic expression
Afina-wow [57]
Less than = subtraction = -
Product = multiplication 

(42 + x) - 18
4 0
3 years ago
Write and equation of the line below ​
blondinia [14]

Answer:

y = 1/4x + 0 or just y = 1/4x

Step-by-step explanation:

First I need the slope so I look at the dots and see how much boxes it goes up and then to the side. So it’s up 2 to the side 8. The slope would be 2/8 but you can simply it by 2 and you get 1/4. And the y intercept is given its zero.

4 0
3 years ago
If Sarah has 50 Nickles and 20 dimes and Bill has 230 pennies and 5 quarters. Who has the more amount of money?
ser-zykov [4K]

Hi,

Your Question states: If Sarah has 50 Nickles and 20 dimes and Bill has 230 pennies and 5 quarters. Who has the more amount of money?

Answer: Sarah

Explanation: Sarah amount is $2.50, because the amount of nickels is 5 cents and if you multiply 5 times 50 you answer becomes $2.50. 20 dimes and every dime is 10 multiples up to $2.00. 230 is $2.30, and 5 quarters each being 25 cents is $1.25 so your answer is Sarah with 50 nickels.

I Hope I Helped!

<em>~KingJupiter</em>

8 0
3 years ago
Read 2 more answers
Evaluate 3_/2 x 5_/2 .....(root)
Nostrana [21]
( \frac{3}{2} )( \frac{5}{2}) =  \frac{15}{2} or  \sqrt{15}  = 3.8 or 4
3 0
3 years ago
Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$
horrorfan [7]

Answer:

A +B+C+D  = 3 is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

A+B+C+D = ? if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under \sqrt (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \   (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, A +B+C+D = 5+6-10+2 = \bold3

5 0
3 years ago
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