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3 years ago

Are the fractions 1/5 5/5 5/1 equivalent? explain.

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

7 0

No .2, 1, 5
it's a fraction so a/b isn't b/a unless a=b

Afina-wow [57]3 years ago

7 0

No, because neither all three numerators or all three denominators are the same.

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the elevation of Death valley, California is -282 feet. the Mississippi river in Illinois has an elevation of 279 feet. which is

polet [3.4K]

Answer:

1 + 1 = 2

Step-by-step explanation:

2+2=4

hope it helps

8 0

3 years ago

CAN SOMEONE HELP ME ASAP? The density of a certain material is such that it weighs 7 ounces for every 2.5 gallons of volume. Exp

lesya [120]

Answer: Density = 0.23 tons per cubic meter.

Step-by-step explanation:

Formula : $Density=\dfrac{Mass(in \ ton)}{Volume (in\ m^3)}$

1 ton = 32000 ounces

⇒ 1 ounce = 0.00003125 ton

⇒ 7 ounces = 7(0.00003125)= 0.00021875 ton

1 gallon = 0.00378541 cubic meter

2.5 gallons = 0.009475 cubic meter

Density= $\dfrac{0.00021875}{0.009475}\text{ tons per cubic meter}$

$\dfrac{21875}{94750}\text{ tons per cubic meter}\approx0.23\text{ tons per cubic meter}$

Hence, Density = 0.23 tons per cubic meter.

5 0

4 years ago

Read 2 more answers

ALL IT SAYS IS SLOVE I REALLY NEED HELP PLEASEEE!!! THANK YOUUU

velikii [3]

Answer:

The answer for your question is C

8 0

2 years ago

Can anybody explain how to find range on a data set?

nekit [7.7K]

so lets say your number set is

9 4 7 3 1 6
you take highest and lowest number so 9 and 1
then subtract 9 - 1 = 8 there you have it

4 0

4 years ago

Read 2 more answers

Find a potential function for the vector field

alexdok [17]

(a) We want to find a scalar function $f(x,y,z)$ such that $\mathbf F = \nabla f$ . This means

$\dfrac{\partial f}{\partial x} = 2xy + 24$

$\dfrac{\partial f}{\partial y} = x^2 + 16$

Looking at the first equation, integrating both sides with respect to $x$ gives

$f(x,y) = x^2y + 24x + g(y)$

Differentiating both sides of this with respect to $y$ gives

$\dfrac{\partial f}{\partial y} = x^2 + 16 = x^2 + \dfrac{dg}{dy} \implies \dfrac{dg}{dy} = 16 \implies g(y) = 16y + C$

Then the potential function is

$f(x,y) = \boxed{x^2y + 24x + 16y + C}$

(b) By the FTCoLI, we have

$\displaystyle \int_{(1,1)}^{(-1,2)} \mathbf F \cdot d\mathbf r = f(-1,2) - f(1,1) = 10-41 = \boxed{-31}$

$\displaystyle \int_{(-1,2)}^{(0,4)} \mathbf F \cdot d\mathbf r = f(0,4) - f(-1,2) = 64 - 41 = \boxed{23}$

$\displaystyle \int_{(0,4)}^{(2,3)} \mathbf F \cdot d\mathbf r = f(2,3) - f(0,4) = 108 - 64 = \boxed{44}$

7 0

2 years ago