Answer:
infinitely many solutions
Step-by-step explanation:
Given the simultaneous equation
4x=10+4y... 1
2x-2y=15 .... 2
_____________
4x-4y = 10 * 1
2x-2y = 15 * 2
__________--
4x-4y = 10
4x-4y = 30
Add both equation
8x - 8y = 10+30
8x-8y = 40
Divide though by 8
x-y = 5
x = 5 + y
Since the result gave 1 equation and 2 unknowns, then we will let x =k
k = 5 + y
y = k -5
k can be any integer
(x,y) = (k, k-5)
This show that the equation has infinitely many solutions
Answer:
A.
Step-by-step explanation:
(x − 7)^2=
=x^2 − 14x + 49
Answer:
point B 3 up and down 1
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
first of all, what is mode: it is the highest occuring number in a set of numbers.
now since 12 is supposed to be the mean and it occurs twice but 9 also occurs twice so for 12 to be the mode, we must add one more 12.
therefore the answer is 12
Okay, since she started with $100, then that would be a constant. So the function would start off with f(x)=?+100. Okay, now since she is depositing $25 PER month, then the 'x' varibale would be per month. So the function would be f(x)=25x+100. Now since you want to know the rate of change, just insert the x value as the month. For example, you want to know how much money she has on the 4th month, so you would substitute 4 with x --> f(x)=25(4)+100, which is f(x)=200
