3 years ago

[Problem Solving 2] *

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

7 0

Answer:

Step-by-step explanation:

each daughter has 2 sisters and 2 brothers but each son had 1 brother and 3 sisters

Alex777 [14]3 years ago

3 0

The answer is 5 children

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Question 8 Multiple Choice Worth 1 points)

Anon25 [30]

Answer:

$\dfrac{x}{2}+12=36$

Step-by-step explanation:

As it is given that

Both Riley and Francesca commute to work.

And, the Riley takes 12 minutes more than as Francesca as Riley takes 36 minutes

So for determining how many minutes is required for Francesca to get to work we need

Let us assume the time taken by Francesca to get to work is x

So, the time taken by Riley is

$= \dfrac{x}{2}+12$

And, Riley takes 36 minutes to get to work.

So, the equation would be

$\dfrac{x}{2}+12=36$

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3 years ago

What is the area of a triangle<br> with the base of 20 inches and a<br> height of 6 inches?

Nonamiya [84]

Answer:

60 $in^{2}$

Step-by-step explanation:

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2 years ago

Read 2 more answers

Mr. Hebert's class has 36 students and Ms. Green's class has 30 students. For a class competition, each class must be divided in

Dominik [7]

Answer: try question cove just saying

8 0

3 years ago

How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

$(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n$

$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

$\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)$

Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

$y=x^n\implies y'=nx^{n-1}$

4 0

3 years ago

Free points insta: (jqyneii) giving Brainliest to the first person :D make sure to get outside its good for you ily <3

kiruha [24]

Answer:

THANKS FOR THE POINTS

Step-by-step explanation:

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2 years ago