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3 years ago

10

Feel great. smell great," goes the warm, lilting theme song of a television ad for perfume, as the model dances through a field

of flowers. why would this ad be most likely to work

1 answer:

ira [324]3 years ago

6 0

The likely reason as to why this ad is most likely to work is because of emotional appeals by which they are likely to work well with the social identity products that could be describe and read from the scenario above.

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When sold at a 40% discount, a sweater nets the merchant a 20% profit on the wholesale cost at which he initially purchased the

Airida [17]

Answer:

100%

Explanation:

Let the normal retail price of the sweater be 'SP' and the cost price be 'CP'

Therefore,

The selling price = SP - 40% of SP = SP - 0.4SP = 0.6SP

Now,

the profit = 20% of CP = 0.2CP

also,

Profit = Selling Price - Actual price

or

0.2CP = 0.6SP - CP

or

1.2CP = 0.6SP

Or

CP = 0.5SP

or

SP = 2CP

thus,

Increase percentage in sweater marked up from wholesale at its normal retail price

= $\frac{SP-CP}{CP}\times 100$

or

= $\frac{2CP-CP}{CP}\times 100$

= 100%

3 0

2 years ago

The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana

storchak [24]

Answer:

a) $P(492$

And we can use excel or the normal standard table to find this probability:

$P(-0.949 < Z< 0.949)= P(Z$

b) $P(505$

And we can use excel or the normal standard table to find this probability:

$P(-0.949 < Z< 1.898)= P(Z$

c) $P(484$

And we can use excel or the normal standard table to find this probability:

$P(-1 < Z< 1)= P(Z$

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

$X \sim N(502,100)$

Where $\mu=502$ and $\sigma=100$

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)$

And for this case we want this probability:

$P(502-10 < \bar X < 502+10)$

And for this case we can use the z score given by:

$z= \frac{\bar X -\mu}{\sigma_{\bar x}}$

And if we use this formula we got:

$P(492$

And we can use excel or the normal standard table to find this probability:

$P(-0.949 < Z< 0.949)= P(Z$

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

$X \sim N(515,100)$

Where $\mu=515$ and $\sigma=100$

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)$

And for this case we want this probability:

$P(515-10 < \bar X < 515+10)$

And for this case we can use the z score given by:

$z= \frac{\bar X -\mu}{\sigma_{\bar x}}$

And if we use this formula we got:

$P(505$

And we can use excel or the normal standard table to find this probability:

$P(-0.949 < Z< 1.898)= P(Z$

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

$X \sim N(494,100)$

Where $\mu=494$ and $\sigma=100$

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)$

And for this case we want this probability:

$P(494-10 < \bar X < 494+10)$

And for this case we can use the z score given by:

$z= \frac{\bar X -\mu}{\sigma_{\bar x}}$

And if we use this formula we got:

$P(484$

And we can use excel or the normal standard table to find this probability:

$P(-1 < Z< 1)= P(Z$

3 0

3 years ago

What is State Farm's Promise of Customer Satisfaction on recycled sheet metal?

MakcuM [25]

The State Farm's Promise of Customer Satisfaction on recycled sheet metal is for at least as long as the OEM would have warranted its new replacement part. Thus 2nd option is correct.

<h3>What is Customer satisfaction?</h3>

Customer Satisfaction refers to the fulfillment of the needs and the desire of the customer by making the product as per there requirement. It is the measurement of the how much the customer is satisfied with the product.

In the above case, the State Farm provides the services to the customer by selling the metal sheets. They had promised the customer for providing the original equipment manufactured to be replaced with the new till the life span of the metal sheets.

Thus the correct option is 2nd.

Learn more about the Customer satisfaction here:

brainly.com/question/15298944

#SPJ1

3 0

2 years ago

Which of the following is not true of generally accepted accounting principles?

andrey2020 [161]

Answer:

(A) GAAP does not have substantial authoritative support.

Explanation:

Choices B to C are true about GAAP.

Now, Choice A is not true since GAAP also includes detailed procedures and practices that provide a <u>standard</u> and not only broad guidelines of general application and this will imply that GAAP has a <u>substantial authoritative support.</u>

<u></u>

Also it is called "Generally Accepted Accounting Principles" for this reason.

8 0

3 years ago

A company that produces running shoes specifically for customers with low arches, utilizes a market-orientation approach and lik

masya89 [10]

Answer: The correct answer is "c. employs customer relationship management strategies.".

Explanation: Customer relationship management strategies involve a management model of the entire organization, based on customer satisfaction (or market orientation according to other authors). It is an approach to manage the interaction of a company with its current and potential customers.

4 0

3 years ago