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3 years ago

I'm confusedWhat is the answer?

Mathematics

1 answer:

forsale [732]3 years ago

6 0

If c > 0, then f(x - c) is a shift of f(x) by c units to the right, and f(x + c) is a shift by c units to the left.

If d > 0, then f(x) - d is a shift by d units downward, and f(x) + d is a shift by d units upward.

Let g(x) = x. Then f(x) = g(x + a) - b = (x + a) - b. So to get g(x), we translate f(x) to the left by a units, and down by b units.

Note that we can also interpret the translation as

• a shift upward of a - b units, since

(x + a) - b = x + (a - b)

• a shift b units to the right and a units upward, since

(x + a) - b = x + (a - b) = x + (- b + a) = (x - b) + a.

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PLEASE help me with THIS QUESTIOn plz ASAP thank u.

Lyrx [107]

It would be: if you want me to explain let me know

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3 years ago

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During the summer Andrew worked for 5 days each week he worked 8 hours each day

Tema [17]

He made $40 those 5 days.

8•5=40

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3 years ago

Larry buys a tent that is on sale for 25% off the original price. The original price is $80 more than the sale price. What is th

myrzilka [38]

Answer:

The original price of the tent = $320

Step-by-step explanation:

Let the original price be =$ $x$

Discount offered = $25$ % of the orignal price = $\frac{25}{100}\times x=0.25\times x =\$ 0.25x$

Original price is $80 more than sale price

Discount = Original price - Sale price = $80

So, we have

$0.25x=80$

We need to solve for $x$ to find original price

Dividing both sides by $0.25$

$\frac{0.25}{0.25}x=\frac{80}{0.25}\\x=\$320$

∴ The original price of the tent = $320

3 0

3 years ago

In a standard normal distribution, about _________% of the scores fall above a z-score of 3.00

Katarina [22]

The normal rule to remember is 68-95-99.7, i.e. plus or minus three sigma corresponds to 99.7% of the probability. That leaves 0.3% in the two tails, or 0.15% in the tail above 3 sigma.

Answer: 0.15%

7 0

3 years ago

I dont understand this at all. I really need help!

Westkost [7]

Hello!

$\large\boxed{x^{4}}$

Recall that:

$\sqrt[z]{x^{y} }$ is equal to $x^{\frac{y}{z} }$ . Therefore:

$\sqrt[3]{x^{2} } = x^{\frac{2}{3} }$

There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

$(x^{\frac{2}{3} })^{6} = x^{\frac{2}{3}* 6 } = x^{\frac{12}{3} } = x^{4}$

3 0

3 years ago

I'm confusedWhat is the answer?​

I'm confusedWhat is the answer?