Answer:
The value of c that will result in a perfect square trinomial is (3)^2 or 9
The perfect square trinomial is: ![(w+3)^2=139](https://tex.z-dn.net/?f=%28w%2B3%29%5E2%3D139)
Step-by-step explanation:
We need to determine the value of c that will result in a perfect square trinomial.
![w^2+6w+ c =130+c](https://tex.z-dn.net/?f=w%5E2%2B6w%2B%20c%20%3D130%2Bc)
Perfect square trinomial are of form: ![a^2+2ab+b^2=(a+b)^2](https://tex.z-dn.net/?f=a%5E2%2B2ab%2Bb%5E2%3D%28a%2Bb%29%5E2)
Now, the equation given is:
![w^2+6w+ c =130+c](https://tex.z-dn.net/?f=w%5E2%2B6w%2B%20c%20%3D130%2Bc)
Looking at the term 6w, we can write it as 2(w)(3)
We are given: a = w, 2ab = 2(w)(3) so, b will be: (3)^2
So, we will be adding (3)^2 on both sides
![w^2+6w+ c=130+c\\w^2+2(w)(3)+ (3)^2 =130+(3)^2\\The\:left\:side\:becomes: a^2+2ab+b^2\\We\:can\:write\:it\:as: (a+b)^2\\We\:have\:a=w\: and\: b=3\\(w+3)^2=130+9\\(w+3)^2=139](https://tex.z-dn.net/?f=w%5E2%2B6w%2B%20c%3D130%2Bc%5C%5Cw%5E2%2B2%28w%29%283%29%2B%20%283%29%5E2%20%3D130%2B%283%29%5E2%5C%5CThe%5C%3Aleft%5C%3Aside%5C%3Abecomes%3A%20a%5E2%2B2ab%2Bb%5E2%5C%5CWe%5C%3Acan%5C%3Awrite%5C%3Ait%5C%3Aas%3A%20%28a%2Bb%29%5E2%5C%5CWe%5C%3Ahave%5C%3Aa%3Dw%5C%3A%20and%5C%3A%20b%3D3%5C%5C%28w%2B3%29%5E2%3D130%2B9%5C%5C%28w%2B3%29%5E2%3D139)
So, The value of c that will result in a perfect square trinomial is (3)^2 or 9
The perfect square trinomial is: ![(w+3)^2=139](https://tex.z-dn.net/?f=%28w%2B3%29%5E2%3D139)
12 since 12 is not negative. All absolute values r positive
Answer:
288
Step-by-step explanation:
12 x 8 x 3 = 288
Answer:
![26](https://tex.z-dn.net/?f=26)
Step-by-step explanation:
![2n-6](https://tex.z-dn.net/?f=2n-6)
Given that:
![n=16](https://tex.z-dn.net/?f=n%3D16)
To evaluate the expression, we must simply substitute the given value of
, which is
, for
:
![2(16)-6](https://tex.z-dn.net/?f=2%2816%29-6)
Multiply:
![32-6](https://tex.z-dn.net/?f=32-6)
Subtract:
![26](https://tex.z-dn.net/?f=26)
-
To check your work, simply set the given expression equal to our solution,
:
![2n-6=26](https://tex.z-dn.net/?f=2n-6%3D26)
Add
to both sides of the equation:
![2n=32](https://tex.z-dn.net/?f=2n%3D32)
Divide both sides of the equation by the coefficient of
, which is
:
![n=16](https://tex.z-dn.net/?f=n%3D16)
Since it matches the given value of
, our solution is correct!
<span>165/2
Hope this helps (:
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