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lbvjy [14]
3 years ago
5

Mediam of 50+45+49+50+43+49+45+49+45+47+44+51+51+44+47+46+50+44+51+49+43+43+49+45+46+45+51+46

Mathematics
1 answer:
Doss [256]3 years ago
8 0

Answer:

The median is equal 46.5

Step-by-step explanation:

to find the median, we will need to rearrange the numbers in ascending order, so we will have

43, 43, 43, 44, 44, 44, 45, 45, 45, 45, 45, 46, 46, 46, 47, 47, 49, 49, 49, 49, 49, 50, 50, 50, 51, 51, 51, 51

Note that there are 28 numbers in total, therefore the median will fall in between the fourteenth and the fifteenth number which are 46 and 47 respectively.

Since we are considering two figures as median, we will need to find the average, which will be

(46 + 47)/2 = 46.5

The median is therefore 46.5

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A carnival charges two different prices for admissions. Adults cost $4 while children cost $1.50. If a total of $5050 was collec
GenaCL600 [577]

Answer:

Step-by-step explanation:

We have to have 2 different equations to solve this.  One equation will represent the number of tickets sold while the other represents the money collected when the tickets were sold.

We know that adult tickets + children tickets = 2200 tickets.

That's the "number of tickets" equation.  Let's call adult tickets "a" and children's tickets "c".  So a + c = 2200

Now if each adult costs $4, then the expression that represents that as a cost is 4a.  If there is 1 adult, the cost is $4(1) = $4; if there are 2 adults, the cost is $4(2) = $8; if there are 3 adults, the cost is $4(3) = $12, etc.

The same goes for the children's tickets.  If each child's ticket is $1.50, then the expression that represents the cost of a child's ticket is 1.5c (we don't need the 0 at the end; it doesn't change anything to drop it off).  The total money brought in from the cost of these tickets was $5050, so

4a + 1.5c = 5050

Let's solve the first equation for a.  If a + c = 2200, then a = 2200 - c.  Sub that into the second equation and solve it for c:

4(2200 - c) + 1.5c = 5050 and

8800 - 4c + 1.5c = 5050 and

-2.5c = -3750 so

c = 1500

That means that there were 1500 children's tickets sold.  If a + c = 2200, then a + 1500 = 2200 so

a = 2200 - 1500 so

a = 700

There were 1500 children's tickets sold and 700 adult tickets sold.

7 0
3 years ago
Please help me with my problem
Doss [256]
D and F are not equivalent to ax+bx+ac+bc+
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Answer:

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Answer:

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Step-by-step explanation:

The process of a reflection across the y axis is simply just switching the x value in (x,y) to a negative. So, (4,-7) and then make 4, a -4. So the resulting image is (-4,-7)

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Answer:

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