Ask question

Ask question

All categories

3 years ago

14

I am a three digit number. I am greater than 312 but less than 348. The digit in my tens place equals 5+2. The sum of my digits

is 18. What number am I?

1 answer:

nevsk [136]3 years ago

3 0

The answer would be 378

You might be interested in

Choose the fraction that has not been reduced to simplest form.

Gennadij [26K]

We are required to choose the fraction that has not been reduced to simplest form

The fraction that has not been reduced to simplest form is 19/38 and 10/18

1. 21 / 34 is in its simplest form

factors of 21 = 1, 7 and 21

factors of 34 = 1, 2, 17 and 34

No common factor of 21 and 34 except 1

2. 15/16

factors of 15 = 1, 3, 5, 15

Factors of 16 = 1, 2, 4, 8 and 16

No common factor of 15 and 16 except 1

3. 19/38

factors of 19 = 1, 19

factors of 38 = 1, 2, 19 and 38

divide both numerator and denominator by 19

So,

19 / 38 = 1/2

4. 10/18

factors of 10 = 1, 2, 5 and 10

factors of 18 = 1, 2, 3, 6, 9 and 18

So,

10/18

divide both numerator and denominator by 2

= 5/9

Read more:

brainly.com/question/18069

7 0

3 years ago

Match the story with an equation.

Basile [38]

Answer:

P=length of each of the 4 pieces

(8' - 0.25')/4=P

Step-by-step explanation:

P=length of each of the 4 pieces

(8' - 0.25')/4=P

3 0

3 years ago

The word problem I just sent

suter [353]

P = 2W + 2L

P - 2L = 2W

W = $\frac{P - 2L}{2}$

8 0

3 years ago

What is the length of 7.2 ft & 9.6ft

BaLLatris [955]

Answer:

16.8ft !

7.2 + 9.6 = 16.8 ft .

3 0

2 years ago

Read 2 more answers

Can someone PLEASE help me with Trigonometry???

Svetach [21]

$\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}$

but anyway, the numerator will give the angles, and θ is just half of each

$\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025$

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there

7 0

3 years ago