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slamgirl [31]
3 years ago
14

I am a three digit number. I am greater than 312 but less than 348. The digit in my tens place equals 5+2. The sum of my digits

is 18. What number am I?
Mathematics
1 answer:
nevsk [136]3 years ago
3 0
The answer would be 378
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What percent of the muffins were carrots
Readme [11.4K]

Answer:

0%

Step-by-step explanation:

Muffins aren't carrots, unless they are carrot muffins.

6 0
3 years ago
(x^3+3x^2-x-3)÷(x-1) solve using long division must show work​
garik1379 [7]
The answer to the question

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4 years ago
Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.
Zarrin [17]

Answer:

The answer is 7/36.

Step-by-step explanation:

First, you find out how many possible outcomes there are from rolling a pair of dice. On one cube, you can roll a 1,2,3,4,5, or 6; so there are 6 outcomes. Since there are two cubes, you multiply 6 by itself to get a total of 36 possible outcomes. Next, you find the probability of the sum of the numbers rolled being an even number; the possibilities are 2,4,6,8,10, or 12, which is 6/36. The probability of rolling a multiple of 5; the one possibility is just 5, since we already accounted for rolling a 10 as an even number. So that is 1/36. The word <u>or</u> says that we add the two probabilities, so the final answer is 6/36+1/36=7/36.

6 0
3 years ago
A triangle has side lengths of 9 in, 13 in, and 20 in. What is the measurement of this triangle's largest angle?
Rama09 [41]

1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

     i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

      ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2.

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)&#10;&#10;400=81+169-234(cosA)   150=-234(cosA)&#10;&#10;cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°,

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc

6 0
3 years ago
Read 2 more answers
Write the equation in standard form for the circle that has a diameter with endpoints (- 1, 12) and (- 1, 8)​
matrenka [14]

Answer:

The equation in standard form is (x + 1)^{2} + (y - 10)^{2} = 4

Step-by-step explanation:

The distance from (-1, 12) to (-1, 8) = 4 = diameter of the circle.  So, 2 = radius

The center of the circle is at (-1, 10)

The equation in standard form is (x + 1)^{2} + (y - 10)^{2} = 4

3 0
3 years ago
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