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2 years ago

14

I am a three digit number. I am greater than 312 but less than 348. The digit in my tens place equals 5+2. The sum of my digits

is 18. What number am I?

1 answer:

nevsk [136]2 years ago

3 0

The answer would be 378

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Select all that apply.

Kay [80]

Answer:

Isosceles and Scalene

Step-by-step explanation:

I did some research and plus we learned about angles and triangles in Geometry.

Plz click the Thanks button!

<Jayla>

6 0

3 years ago

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

2 years ago

Select all the correct graphs.<br> Choose the graphs that indicate equations with no solution.

Natali [406]

Answer:

The first and last graph.

General Formulas and Concepts:

<u>Algebra I</u>

Solving systems of equations graphically

Step-by-step explanation:

In order for a systems of equations to have a solution set, the 2 graphs must intersect at at least 1 point. Here, we see that graphs 1 and 5 do not intersect each other at all.

Therefore, the rest of the graphs have solutions and #1 and #5 do no have any solutions.

3 0

2 years ago

Ratio of 1/16 to 1/16

aleksklad [387]

Answer 1:16 is the answer

7 0

2 years ago

Read 2 more answers

Use area of squares to visualize Pythagorean theorem

docker41 [41]

We know that the Pythagorean Theorem is a² + b² = c² and that the area of a square is l x w.

Firstly, we'll have to find the two measures of the triangle that correspond to the areas.

Since the figures are squares, we know that the length and width values must be the same.

We could square the numbers to find the side lengths, however we would have to square them again when substituting for the Pythagorean Theorem, so we can leave them as-is and adjust the equation accordingly.

(33) + b² = (44)

Next, we'll subtract our smaller value from our larger.

b² = (11)

Once again, we could find the square root of this number, but we'd just have to square it again to find the area of the square, so we can just simply write our answer as 11 units.

Therefore, the area of the square is 11 units!

<em>Hope this helped! :)</em>

5 0

2 years ago