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marissa [1.9K]
3 years ago
14

B) A car drives at a speed of 90kmth for 2 hours and 20 minutes How far does the car onve?

Mathematics
2 answers:
Minchanka [31]3 years ago
6 0

Answer:

210 km

Step-by-step explanation:

90 * 2 is 180 (distance over 2 hours)

20 minutes is .333 hours, so 90*0.333 is about 30 km

and 180+30 is 210.

Amanda [17]3 years ago
3 0

Answer:

210km

Step-by-step explanation:

2 hours=90km×2hr=180

20mins converted to a fraction is 0.333hr

90×0.333=29.97

Round 29.97 to 30

180+30

=210

Hope this helps u

Here u go hope it helps

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234 students in 9 different classrooms. What is the ratio of students to classrooms?
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Answer:

26 students per classroom

Step-by-step explanation:

To solve this, the ratio 234 students:9 classrooms must be converted to:

s students:1 classroom

To convert the ratio, 9 was divided by 9 to get 1, and so you must also divide 234 by 9 to maintain the same ratio, which gives us the answer:

26 students: 1 classroom

5 0
2 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Can you do LCM in division method of 550,750,900 plzz​
mr_godi [17]

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2 | <u>2</u><u>7</u><u>5</u><u>,</u><u>3</u><u>7</u><u>5</u><u>,</u><u>4</u><u>5</u><u>0</u>

3 |<u> </u><u>2</u><u>7</u><u>5</u><u>,</u><u>3</u><u>7</u><u>5</u><u>,</u><u>2</u><u>2</u><u>5</u>

<u>3</u><u> </u>| <u>2</u><u>7</u><u>5</u><u>,</u><u>1</u><u>2</u><u>5</u><u>,</u><u>7</u><u>5</u>

5 | <u>2</u><u>7</u><u>5</u><u>,</u><u>1</u><u>2</u><u>5</u><u>,</u><u>2</u><u>5</u>

5 | <u>55,25,5</u>

5 | <u>1</u><u>1</u><u>,</u><u>5</u><u>,</u><u>5</u>

11 | <u>1</u><u>1</u><u>,</u><u>1</u><u>,</u><u>1</u>

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7 0
2 years ago
Given g(x) = 3x + 3 , find g(k)
xxTIMURxx [149]

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6 0
3 years ago
For four weeks in June Cameron baked 3 1/4 miles each week and swim 2 1/2 miles each week for three weeks in July he baked 4 3/4
Tems11 [23]
For June:
 Bike:
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 Total:
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 Answer:
 
the total distance Cameron bike and swim in July compared to the total distance he bike in swim in June was 1.75 miles greater
6 0
2 years ago
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