1) c) y = 500 * 2^x
In year 1, x = 1 and the population is 500 * 2^1 = 1000
In year 2, this doubles to 500 * 2^2 = 500 * 4 = 2000
ans so on
This model describes the population doubling every year
2)
A) 3 (1/2)^x and C) (0.25)^x
These numbers reduce as x increases because there is a number with an absolute value less than 1 is being raised to the power of x. They also will never totally reach zero or become negative, but will approach zero as x becomes very large.
Answer:
12 m/s²
Step-by-step explanation:
mass of the car = 50 kg
The net force applied to the car is 800 - 200 = 600 N
Form the Newton's second law:
F = m*a
where F is the net force applied to the object, m is the mass of the object, and a is the acceleration of the object.
Then, the acceleration of the car (in m/s²) is:
a = F/m
a = 600/50
a = 12 m/s²
Answer:
850 leaves were on the tree initially.
Same as;
2/5 + 1/5 + 3/10 + (remaining leaves 1/10) = 1
4/10 + 2/10 + 3/10 + 1/10
10 x 85 = 850
Step-by-step explanation:
2/5 wk 1 fall off
1/5 wk 2 fell off
3/5 x 1/2 = 3/10 wk 2 stayed on tree
1/3 x 3/10 = 1/10 wk 3 stayed on
2/5 + 1/5 + 3/10 = 9/10 = 0.9 fall off in total
10/10 - 9/10 = 1/10 left on tree
1/10 = 85
10 x 85 = 850 leaves.
Hi there!
6/7 itself is already simplified in it's smallest form.
6/7 = 6/7.
In a decimal form this is 0.857143.
Hope this helps!
The easiest way to graph this equation is using the x and y intercepts. Plug zero in for x to solve for y, then plug zero in got y to solve for x.
