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3 years ago

Please help me on question 4!! asap

Mathematics

1 answer:

Volgvan3 years ago

8 0

I belive your actually right and the letter answer is H (im really not sure)

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cupoosta [38]

3 because I did the quiz and got it right txt me if you need help

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3 years ago

Read 2 more answers

Please help me look at the attached picture

Lady bird [3.3K]

Answer:

Q(-10) = 299

Step-by-step explanation:

$Q(x) = 3x^{2} - 1$ $Q(-10) = 3(-10)^{2} - 1$

$Q(-10) = 3(100) - 1$ (-10 to the second power is 100 (negative times a negative equals a positive)

$Q(-10) = 300 - 1$ 3 times 100 equal 300

$Q(-10) = 299$

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3 years ago

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777dan777 [17]

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2 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Ksju [112]

Answer:converge at $I=\frac{1}{3}$

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int^{\infty}_{3}\frac{1}{x^2}dx$

integration of $\frac{1}{x^2}$ is - $\frac{1}{x}$

$I=\left [ -\frac{1}{x}\right ]^{\infty}_3$

substituting value

$I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]$

$I=-\left [ 0-\frac{1}{3}\right ]$

$I=\frac{1}{3}$

so the value of integral converges at $\frac{1}{3}$

8 0

3 years ago

Find the difference.

sergeinik [125]

The difference is 4hrs because 6-2 is 4

3 0

3 years ago