Square is 19 yd.² what is the length of each side

For each function, what is the output of the given input?

ki77a [65]

Answer:

1. d. 10.

2. d. 35t + 2.75; $142.75.

Step-by-step explanation:

1. f(-2) = -2*-2 + 6

= 4 + 6

= 10.

2. The answer is 35t + 2.75

and the cost of 4 tickets = 35*4 + 2.75 = $142.75.

4 0

3 years ago

The quarterly returns for a group of 6161 mutual funds are well modeled by a Normal model with a mean of 6.16.1% and a standard

Shtirlitz [24]

Answer:

a) The cut off value of the highest 50% is 6.16%.

b) The cut off value of the highest 16% is 8.8%.

c) The cut off value of the lowest 2.5% is 0.7%.

d) The cut off values of the middle 68% is 3.4% for the lower bound and 8.8% for the higher bound.

Step-by-step explanation:

The 68–95–99.7 rule is an empirical rule to remember the percentage of values that lie within a band around the mean in a normal distribution with a width of two, four and six standard deviations respectively.

a) Cut off value of the highest 50%

It corresponds to the half that has the higher returns, which are the ones that are above the mean (0 standard deviation). The cut off value in this case is the mean x=6.16%.

b) Cut off value of the highest 16%

In this case, we use the 68 rule-value, which means that 68% of the values lies within a band around the mean with a width of two standard deviations.

The percentage that lies out of this band is 100%-68%=32%, of which 16% lies above the band (the highest 16%) and 16% lies below the band.

We can estimate, according to this rule, that the highest 16% are above the cutoff value X of μ+1σ:

$X=\mu+\sigma=6.1%+2.7%=8.8%$

The cut off value of the highest 16% is 8.8%.

c) Cut off of the lowest 2.5%

In this case, we use the 95 rule.

The lowest 2.5% lies below two standards deviation less of the mean

$X=\mu-2*\sigma=6.1%-2*2.7%=0.7%$

The cut off value of the lowest 2.5% is 0.7%.

d) Cut off of the middle 68%

In this case we calculate the band within one standard deviation.

$X_{low}=\mu-\sigma=6.1%-2.7%=3.4%\\\\X_{high}=\mu+\sigma=6.1%+2.7%=8.8%$

The cut off values of the middle 68% is 3.4% for the lower bound and 8.8% for the higher bound.

6 0

2 years ago

For the hypothesis test H0: μ = 10 against H1: μ >10 and variance known, calculate the Pvalue for each of the following test

Basile [38]

Answer:

a) $p_v =P(Z>2.05)=1-P(z$

b) $p_v =P(Z>-1.84)=1-P(z$

c) $p_v =P(Z>0.4)=1-P(z$

Step-by-step explanation:

Some previous concepts

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.

A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".

The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"

The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

Hypothesis

Null hypothesis: $\mu=10$

Alternative hypothesis: $\mu >10$

If the random variable is distributed like this: $X \sim N(\mu,\sigma)$

We assume that the variance is known so the correct test to apply here is the z test to compare means, the statistic is given by the following formula:

$z_o=\frac{\bar X -\mu}{\sigma}$

Since we have the values for the statistic already calculated we can calculate the p value using the following formulas:

Part a

$p_v =P(Z>2.05)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(2.05,0,1,TRUE)"

Part b

$p_v =P(Z>-1.84)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(-1.84,0,1,TRUE)"

Part c

$p_v =P(Z>0.4)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(0.4,0,1,TRUE)"

Conclusions

If we use a reference value for the significance, let's say $\alpha=0.05$ . For part a the $p_v$ so then we can reject the null hypothesis at this significance level.