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Talja [164]
3 years ago
12

A central angle θ in a circle of radius 4 m is subtended by an arc of length 5 m. find the measure of θ in degrees. (round your

answer to one decimal place.)
Mathematics
1 answer:
koban [17]3 years ago
5 0

Answer:

\theta=71.6\°

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference is equal to

C=2\pi r

we have

r=4\ m

substitute the values

C=2\pi (4)=8 \pi\ m

step 2

Remember that

360 degrees subtends the arc of length  8 \pi\ m (circumference)

so

by proportion

Find the measure of θ by an arc of length 5 m

assume \pi=3.1416

\frac{360}{8\pi}=\frac{\theta}{5}\\ \\ \theta=360*5/8\pi \\ \\ \theta=71.6\°

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I need he,p i have to finish this by 12:30!!
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Answer:

a and c

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3 years ago
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Enter the resulting inequality.<br> -9 ≤ -6; Add 15 to both sides<br>​
inessss [21]

Step-by-step explanation:

-9+15=6, -6+15=9

So,

6 < 9

3 0
3 years ago
(x^2-5x+6)+(3x^2-8x-2)
Zarrin [17]

Answer:

4x^2-13x+4

Step-by-step explanation:

1. Add together all like terms ( so x^2+3x^2=4x^2)

2. once you add all your like terms. order the numbers from biggest to smallest (4x^2'-13x+4)

*You'll know which is biggest by the exponent!

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3 years ago
Will give Brainliest (:
olya-2409 [2.1K]

Answer:


Step-by-step explanation:

2x^2+8x-12=0

with form

ax^2+bx+c=0


move c to the other side

2x^2+8x=12


x^2 is multiplied -> divide equation by 2

x^2+4x=6


complete square:

divide b=4 by 2

4*1/2=2


square 2

2^2=4


add 4 to both sides

x^2+4x=6

x^2+4x+4=6+4

x^2+4x+4=10


transform to polynom

(x+2)^2=10


this left side is option B multiplied by a factor of 16 and therefore equal:

(4x + 8)^2

(4*4)x^2+(4*2*8)x+8*8

16x^2+64x+64

x^2+4+4


bonus: calculate root

x+2=+/-sqrt(10)

x=-2+/-sqrt(10)


<h2 /><h2>so it is option B</h2>
  • <em>2x^2 + 8x - 12 = 0..divide by 2</em>
  • <em>x^2 + 4x - 6 = 0</em>
  • <em>x^2 + 4x = 6...add 4 to both sides of the equation</em>
  • <em>x^2 + 4x + 4 = 6 + 4</em>
  • <em>(x + 2)^2 = 10....<== ur constant is 10</em>
  • <em>x + 2 = (+-)sqrt 10</em>
  • <em>x = -2 (+ - ) sqrt 10</em>
  • <em></em>
  • <em>x = -2 + sqrt 10</em>
  • <em>x = -2 - sqrt 10</em>
  • <em></em>
  • <em></em>
  • <em></em>
5 0
3 years ago
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