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Talja [164]
3 years ago
12

A central angle θ in a circle of radius 4 m is subtended by an arc of length 5 m. find the measure of θ in degrees. (round your

answer to one decimal place.)
Mathematics
1 answer:
koban [17]3 years ago
5 0

Answer:

\theta=71.6\°

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference is equal to

C=2\pi r

we have

r=4\ m

substitute the values

C=2\pi (4)=8 \pi\ m

step 2

Remember that

360 degrees subtends the arc of length  8 \pi\ m (circumference)

so

by proportion

Find the measure of θ by an arc of length 5 m

assume \pi=3.1416

\frac{360}{8\pi}=\frac{\theta}{5}\\ \\ \theta=360*5/8\pi \\ \\ \theta=71.6\°

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Step-by-step explanation:

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3 years ago
PLEASE HELP‼
stellarik [79]

D. 75 cm

Step-by-step explanation:

fill in the y with 20.5, so you get 20.5=0.3x-2. Add the 2 to the 20.5 so you get 22.5=0.3x. Divide both by 0.3 to get 75=x.

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4 0
3 years ago
What is 75% of 180?​
OverLord2011 [107]

Hello There!

75% of 180 is 135.

Converting Percent To Decimal.

p = 75%/100 = 0.75

Y = 0.75 * 180

Y = 135

3 0
3 years ago
Read 2 more answers
3) Last year Kerry’s take home pay was £15 000 She spent 40% of her take home pay on rent. She used the rest of her take home pa
gregori [183]
3,000. You take 15,000 and multiply by .4 to get how much she spent on rent (6,000). They you subtract the rent money from her total pay to get her money that she spent on living expenses, clothes and entertainment in total (9,000). Since she spent her money in six parts (3+2+1), you divide 9,000 by 6 to get 1,500 to get each part. Since for entertainment she has two parts you multiply 1,500 by 2 to get 3,000.
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3 years ago
What is the solution to the system of equations below?<br>2x+3y = 17<br>3x+6y= 30​
brilliants [131]

Answer:

<h2>x = 4, y = 3 → (4, 3)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}2x+3y=17&\text{multiply both sides by (-2)}\\3x+6y=30\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-4x-6y=-34\\3x+6y=30\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-x=-4\qquad\text{change the signs}\\.\qquad x=4\\\\\text{put the value of x to the first equation:}\\\\2(4)+3y=17\\8+3y=17\qquad\text{subtract 8 from both sides}\\3y=9\qquad\text{divide both sides by 3}\\y=3

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3 years ago
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