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3 years ago

Ed wants to buy a large bag of dog food for $41.00. If sales tax is 7%, how much tax will he have to pay.

Mathematics

2 answers:

Galina-37 [17]3 years ago

6 0

Answer:

The answer is 43.87

Step-by-step explanation:

Stolb23 [73]3 years ago

6 0

The tax would be $2.87 for a total amount of $43.87

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Please help me with this problem

tigry1 [53]

Answer:

A- 30,968 + 31,211

Step-by-step explanation:

Since 62,179 minus 31,211 is equal to 30968, 30968 plus 31,211 can be used to help check the answer for 62,179 minus 31,211.

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3 years ago

Kenneth drove 180.9 miles in hours. What was his average speed?

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3 years ago

How about this one. can.an expert help

Anarel [89]

To find the answer for the second question, add £114.00 to £150. This adds up to £264.00.

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3 years ago

Dy/dx if y = Ln (2x3 + 3x).

NeTakaya

Answer:

$\frac{6x^2+3}{2x^3+3x}$

Step-by-step explanation:

You need to apply the chain rule here.

There are few other requirements:

You will need to know how to differentiate $\ln(u)$ .

You will need to know how to differentiate polynomials as well.

So here are some rules we will be applying:

Assume $u=u(x) \text{ and } v=v(x)$

$\frac{d}{dx}\ln(u)=\frac{1}{u} \cdot \frac{du}{dx}$

$\text{ power rule } \frac{d}{dx}x^n=nx^{n-1}$

$\text{ constant multiply rule } \frac{d}{dx}c\cdot u=c \cdot \frac{du}{dx}$

$\text{ sum/difference rule } \frac{d}{dx}(u \pm v)=\frac{du}{dx} \pm \frac{dv}{dx}$

Those appear to be really all we need.

Let's do it:

$\frac{d}{dx}\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot \frac{d}{dx}(2x^3+3x)$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (\frac{d}{dx}(2x^3)+\frac{d}{dx}(3x))$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (2 \cdot \frac{dx^3}{dx}+3 \cdot \frac{dx}{dx})$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (2 \cdot 3x^2+3(1))$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{1}{2x^3+3x} \cdot (6x^2+3)$

$\frac{d}{dx}(\ln(2x^3+3x)=\frac{6x^2+3}{2x^3+3x}$

I tried to be very clear of how I used the rules I mentioned but all you have to do for derivative of natural log is derivative of inside over the inside.

Your answer is $\frac{dy}{dx}=\frac{(2x^3+3x)'}{2x^3+3x}=\frac{6x^2+3}{2x^3+3x}$ .

3 0

3 years ago

A person invest 7500 dollars in a bank. The bank pays 6 interest compounded semi-annually. To the nearest tenth of a year,how lo

Kamila [148]

Answer:

Step-by-step explanation:

I clicked see solution

T=5 years

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2 years ago