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Luba_88 [7]
3 years ago
7

Find the value of x

Mathematics
2 answers:
Grace [21]3 years ago
6 0

Answer:

1.2 degrees

Step-by-step explanation:

kodGreya [7K]3 years ago
5 0
I can’t see the whole question.
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The weights of five grapefruits are 7.47 ounces, 7.23 ounces, 6.46 ounces, 7.48 ounces, and 6.81 ounces. Using the clustering es
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Answer: The approximate total weight of the grapefruits, using the clustering estimation technique is B. 35 ounces.

8 0
3 years ago
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What is the perimeter of the shape?<br> 2 yd<br> 3 yd<br> 5 yd<br> 4 yd<br> 2 yd<br> 6 yd
Kaylis [27]

Answer:

22 yards

Step-by-step explanation:

P = 5+2+3+4+2+6

P = 22

8 0
3 years ago
Suppose we are making predictions of the dependent variable y for specific values of the independent variable x using a simple l
e-lub [12.9K]

Answer:

width (C.I) ∠ width (P.I)

Step-by-step explanation:

In statistics, a confidence interval (C.I) is known as an interval estimate which is computed using the observed data that might contain the actual value of an unknown parameter. The confidence level is commonly used for estimation before examining the actual data. On the other hand, the prediction interval (P.I) is a range of values that calculate the value of a new observation by considering the existing model developed using the actual data. Therefore, the true statement is:

width (C.I) ∠ width (P.I)

8 0
3 years ago
Please help I'll mark brainliest​
NISA [10]

Answer:

470?

Step-by-step explanation:

I am not fully sure of the answer

7 0
3 years ago
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F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
3 years ago
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