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Sever21 [200]
3 years ago
11

Please help me I am stuck :(​

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

Step-by-step explanation:

This is a definite maybe kind of question.

Start with the 280. It has a range of 280 +/- 10 mL. That means that each serving is between 270 and 290. If she serves exactly 280 every time she will need 22 * 280 = 6160 mL or 6160/1000 = 6.16 L which gives her a margin of 0.340 L or 340 mL

Consider 270 mL

270 mL * 22 = 5940 mL or 5.94 L She has a little over 1/2 L left over. She has enough soup for 22 people.

Finally think about 290 per serving

290 * 22 = 6380. This should work as well providing she has more than 6.38 Liters which is not a slam dunk.  With a leeway of 0.5 L and she only makes 6 Liters, she does not have enough.

So maybe. (Since you can explain this question, you can, I should think, use 0.5 Liters as a leeway).

There is one condition I have not considered and that is what happens if you have 7 Liters of soup? Then the leeway in the serving size does not matter.

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attashe74 [19]
8 + -3 * 2m + (-3)(-5) = 8 + -6m + 15 = 8 + -6m + 15 = (-6m) + (8 + 15 ) = -6m + 23


so the answer is  -6m + 23
8 0
3 years ago
Which of the following options have the same value as 2% of 90? Choose 2 answers: А 0.2.90 B 0.02.90 200.90 2.90 E 2 . 90 100​
Wewaii [24]

Answer:

0.02.90 and 2.90

Step-by-step explanation:

2% of 90 equal to both 0.02.90 because are worth same.

7 0
3 years ago
Find the value of x .
disa [49]

Answer:

-3

Step-by-step explanation:

3 0
3 years ago
The following data on average daily hotel room rate and amount spent on entertainment (The Wall Street Journal, August 18, 2011)
Zielflug [23.3K]

Answer:

a. Predicted Amount = $109.46

b. Confidence Interval = (94.84,124.08)

c. Interval = (110.6883,188.8517)

Step-by-step explanation:

Given

ŷ = 17.49 + 1.0334x.

SSE = 1541.4

a.

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46 --- Approximated

Predicted Amount = $109.46

b.

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46

First we calculate the standard deviation

variance = SSE/(n-2)

v = 1541.4/(9-2)

v = 1541.4/7

v = 220.2

s = √v

s = √220.2

s = 14.839

Then we calculate mean(x) and ∑(x - (mean(x))²

X --- Y -- Mean(x) --- ∑(x - (mean(x))²

148 -- 161 -- 43-- 1849

96 || 105|| -9 || 81

91 ||101 || -14 || 196

110 || 142 || 5 || 25

90 || 100 || -15 || 225

102 || ||120 ||-3|| 9

136 || 167 ||31 ||961

90 || 140 ||-15 ||225

82 || 98 ||-23 || 529

Sum 945 || 1134|| 0 ||4100

Mean (x) = 945/9 = 105

∑(x - (mean(x))² = 4100

α = 1 - 95% = 5%

α/2 = 2.5% = 0.025

tα,df = n − 2 = t0.025,7 =2.365

Confidence interval = 109.46 ± 2.365 * 14.839 √((1/9)+ (89-105)²/4100

Confidence Interval = (109.46 ± 14.62)

Confidence Interval = (94.84,124.08)

c.

ŷ = 17.49 + 1.0334(128)

ŷ = 149.7652

ŷ = 149.77

Interval = 149.77 ± 2.365 * 14.839 √((1/9)+ (128-105)²/4100

Interval = 149.77 ± 39.0817

Interval = (110.6883,188.8517)

3 0
3 years ago
Please help me with this
Tamiku [17]

Answer:

20%

hope it helps you

8 0
3 years ago
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