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lisabon 2012 [21]

3 years ago

8

the lenght of a rectangular storage room is 2 feet longer than its width. What are the dimensions of the room if the perimeter o

f the room is 35 feet?

1 answer:

Ne4ueva [31]3 years ago

6 0

16.5 x 18.5 is the answer to your question

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How would i write a recursive formula for 15625, 6250, 2500, 1000

neonofarm [45]

This is a geometric sequence.

a = 15625,

Common ratio = 6250/15625 = 2500/6250 = 0.4

an for GP = ar^(n - 1)

= 15625*(0.4)^(n - 1)

8 0

3 years ago

I don’t get this please help ASAP

jek_recluse [69]

Answer:

AE = 70

Step-by-step explanation:

Given that ACE is a triangle and B , D , F are mid-points of AC, CE, AE respectively.

⇒ BF, FD, BD are mid-segments.

Mid-segment is a line segment joining mid points of two sides of a triangle,

And it as two properties :

1) mid-segment is always parallel to the third side

2) mid-segment is half in length of the third side

⇒ Here, BD is the mid-segment and is parallel to third side AE

And also BD is half of AE

⇒ AE = 2×BD = 2×35

⇒ AE = 70.

3 0

3 years ago

Given the second order homogeneous constant coefficient equation y′′−4y′−12y=0 1) the characteristic polynomial ar2+br+c is r^2-

Vitek1552 [10]

Answer:

The initial value problem $y(x) = 4 e^{-2x} -3 e^{6 x}$

Step-by-step explanation:

<u>Step1:</u>-

a) Given second order homogenous constant co-efficient equation

$y^{ll} - 4y^{l}-12y=0$

Given equation in the operator form is $(D^{2} -4D-12)y=0$

<u>Step 2</u>:-

b) Let f(D) = $(D^{2} -4D-12)y$

Then the auxiliary equation is $(m^{2} -4m-12)=0$

Find the factors of the auxiliary equation is

$m^{2} -6m+2m-12=0$

m(m-6) + 2(m-6) =0

m+2 =0 and m-6=0

m=-2 and m=6

The roots are real and different

The general solution $y = c_{1} e^{-m_{1} x} + c_{2} e^{m_{2} x}$

the roots are $m_{1} = -2 and m_{2} = 6$

The general solution of given differential equation is

$y = c_{1} e^{-2x} + c_{2} e^{6 x}$

<u>Step 3</u>:-

C) Given initial conditions are y(0) =1 and y1 (0) =-26

The general solution of given differential equation is

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$ .....(1)

substitute x =0 and y(0) =1

$y(0) = c_{1} e^{0} + c_{2} e^{0}$

$1 = c_{1} + c_{2}$ .........(2)

Differentiating equation (1) with respective to 'x'

$y^l(x) = -2c_{1} e^{-2x} + 6c_{2} e^{6 x}$

substitute x= o and y1 (0) =-26

$-26 = -2c_{1} e^{0} + 6c_{2} e^{0}$

$-2c_{1} + 6c_{2} = -26$ .............(3)

solving (2) and (3) by using substitution method

$substitute c_{2} =1- c_{1}$ in equation (3)

$-2c_{1} + 6(1-c_{1}) = -26$

on simplification , we get

$-2c_{1} + 6(1)-6c_{1}) = -26$

$-8c_{1} = -32$

dividing by'8' we get $c_{1} =4$

substitute $c_{1} =4$ in equation $1 = c_{1} + c_{2}$

so $c_{2} = 1-4 = -3$

now substitute $c_{1} =4 and c_{2} =-3$ in general solution

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$

$y(x) = 4 e^{-2x} -3 e^{6 x}$

now the initial value problem

$y(x) = 4 e^{-2x} -3 e^{6 x}$

7 0

4 years ago

Ill mark u brainliest if u answer pls answer fast& its worth 49 points:

defon

B a gf svvhghhfhhfjgh

4 0

3 years ago

I am having trouble with my pre-algebra HW

Ksivusya [100]

Answer:

twesrdtewrhtrdtdrdyudtrerst

Step-by-step explanation:

ewsrfghrtefgsergergesg

7 0

4 years ago

Read 2 more answers