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bagirrra123 [75]
3 years ago
6

Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares

$abcd$ and $aefg$?
Mathematics
1 answer:
Alla [95]3 years ago
8 0
Let the measure of side AB be x, then, the measue of side AE is given by

AE=\sqrt{9^2-x^2}.

Now, ABCD is a square of size x, thus the area of square ABCD is given by

Area=x^2

Also, AEFG is a square of size \sqrt{9^2-x^2}, thus, the area of square AEFG is given by

Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2

<span>The sum of the areas of the two squares ABCD and AEFG is given by

x^2+81-x^2=81

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
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