Answer:
Step-by-step explanation:
56.27 =
50
+ 6
+ 0.2
+ 0.07
Expanded Factors Form:
56.27 =
5 × 10
+ 6 × 1
+ 2 × 0.1
+ 7 × 0.01
Expanded Exponential Form:
56.27 =
5 × 101
+ 6 × 100
+ 2 × 10-1
+ 7 × 10-2
Word Form:
56.27 =
fifty-six and twenty-seven hundredths
1)
n 1 2 3 4 5 6
f(n) 1033 932 831 730 629 528
First term (a₁): <u>1033 </u> Common difference (d): <u>-101 </u>
Explicit rule:
Recursive rule: 




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2)
n 1 2 3 4 5 6
f(n) -39 -29 -19 -9 9 19
First term (a₁): <u> -39 </u> Common difference (d): <u> +10 </u>
Explicit rule:
Recursive rule: 




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3)
n 1 2 3 4 5 6
f(n) 3.75 2.5 1.25 0 -1.25 -2.5
First term (a₁): <u> 3.75 </u> Common difference (d): <u> -1.25 </u>
Explicit rule:
Recursive rule: 




Answer: 1.5
Step by step explain:
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5