45 adult tickets and 80 children tickets were sold
<em><u>Solution:</u></em>
Let "a" be the number of adult tickets sold
Let "c" be the number of children tickets sold
Cost of 1 adult ticket = $ 6
Cost of 1 children ticket = $ 3.50
<em><u>They sold a total of 125 tickets</u></em>
Therefore,
a + c = 125
c = 125 - a --------- eqn 1
<em><u>They made a total of $550. Therefore, frame a equation as:</u></em>
number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = 550
6a + 3.50c = 550 ----------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>
6a + 3.50(125 - a) = 550
6a + 437.5 - 3.50a = 550
2.5a = 112.5
<h3>a = 45</h3><em><u>Substitute a = 45 in eqn 1</u></em>
c = 125 - 45
<h3>c = 80</h3>Thus 45 adult tickets and 80 children tickets were sold