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Tatiana [17]
3 years ago
14

30-5 • 4+2 how do I solve this

Mathematics
1 answer:
Alona [7]3 years ago
3 0
P
E
M
D
A
S

5*4= 20
20+2=22
22-30= answer is 8 :)
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Please help I don’t understand this
enyata [817]

Answer:

  d. √(1/(x+1))

Step-by-step explanation:

Just as operations can be performed on numbers and variables, so can operations be performed on functions. Here, you're asked to simplify the ratio of two functions.

  \displaystyle\left(\frac{g}{f}\right)(x)=\frac{g(x)}{f(x)}=\frac{\sqrt{x-1}}{\sqrt{x^2-1}}=\sqrt{\frac{x-1}{x^2-1}}

At this point, you're supposed to know the factoring of the difference of squares:

  \displaystyle=\sqrt{\frac{x-1}{(x-1)(x+1)}}=\boxed{\sqrt{\frac{1}{x+1}}}

4 0
2 years ago
Factor −1/4 out of −1/2x−5/4y..ㅤ
hammer [34]

Answer:

  • - 1/4 (2x + 5y)

Step-by-step explanation:

Divide each term by - 1/4 first

  • -1/2x ÷ (- 1/4) = 1/2x × 4 = 2x
  • -5/4y ÷ (- 1/4) = 5/4y × 4 = 5y

Now facor out - 1/4

  • - 1/2x - 5/4y =
  • - 1/4 (2x + 5y)
3 0
2 years ago
I need to know what is 2x+4
morpeh [17]

Answer:

6

Step-by-step explanation:

hope this helps

3 0
3 years ago
Read 2 more answers
Help<br> Pls ppl that are good in math
3241004551 [841]
It’s a black picture. We can’t help with that
5 0
3 years ago
I need help on 18 and 19 PLS HELP ME ILY I WILL MARRY U I WILL LOVEEE U FOR ETERNITY
Dmitriy789 [7]

Oof, this is surely a tough one.  But, if I'm looking at this correctly, than I think you were in the right mindset when trying to figure both of them out.  Like, for #18, think about the formula; P(B|A) = P(A and B)/P(A).  So, based on the question, you can let not rolling a 1 on the blue cube be A, and rolling a 1 on the red cube be B.  Now, personally, I prefer using the decimals when heading into the equations, but I'll convert the product into a fraction for the instruction's sake.  0.02777777778 + 0.13888888889 = 1/6.  1/6 ≈ 17.7%.  You can do the same for #19, the overall outcome would be 5/6, which would be about 83%.  Now, that's just me really attempting my hand at it, I will say, Math is far from my strong suite.  But, in all honesty, I really am doing my best to help (and no, it's not because of what you offered, lol, more rather I want to help people who struggle with the same problems I do).  Anyways, I hope this helps, and if you need more information, or anything, just let me know!  Wish ya the best of luck!!  ^u^

5 0
3 years ago
Read 2 more answers
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