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marissa [1.9K]
3 years ago
11

Two squares are attached to the sides of a quarter circle as shown.

Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0
First, you have to split the figure into three shapes, two squares and 1/4 of a circle

Now find the area of the two square
A = lw
A= (10)(10)
A= 100

Now that you have the area measurement for both squares you need to find the measurement of the 1/4 of the circle.

A = \pi r^{2}
A = (3.14)(10) ^{2}
A = (3.14)(100)
A= 314

But that measurement is for the whole circle so you have to divide it by four
A = 314/4
A = 78.5
Now that you have the measurements for all three shapes of the figure you can add them up to get the entire areas of the figure
A = 78.5 + 100 + 100A = 278.5
So the area for the figure is 278.5 square mm
The answer is D

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3 years ago
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3 years ago
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PPPLLLZZZ HELP I'LL GIVE BRAINLIEST
kati45 [8]

Allen's work is not written properly so I have rearranged it as shown below:


Original problem) –8.3 + 9.2 – 4.4 + 3.7.

Step 1) −8.3 + 9.2 + 4.4 + 3.7 Additive inverse

Step 2) −8.3 + 4.4 + 9.2 + 3.7 Commutative property

Step 3) −8.3 + (4.4 + 9.2 + 3.7) Associative property

Step 4) −8.3 + 17.3


We can see that in step 1), Allen changed -4.4 into +4.4 using additive inverse. Notice that we are simplifying not eliminating -4.4 as we do in solving some equation. Hence using additive inverse is the wrong step.


Alen should have collect negative numbers together and positive numbers together.

Add the respective numbers then proceed to get the answer.


–8.3 + 9.2 – 4.4 + 3.7

= –8.3 – 4.4 + 9.2 + 3.7

= -12.7 + 12.9

= 0.2



6 0
3 years ago
Read 2 more answers
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lilavasa [31]
Use the Pythagorean theorem. We have legs with lengths of 15 and 20 miles, now let's solve for the hypotenuse.

a=15
b=20
c=?

a^2+b^2=c^2
15^2+20^2=c^2
c^2=400+225=625
c=25

Your answer is 25 miles. Hope this helps! :)
7 0
3 years ago
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