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kykrilka [37]
3 years ago
7

PLZ HURRY IT'S URGENT!!!

Biology
1 answer:
Natalija [7]3 years ago
5 0
Ok it is d,
Sorry if my English bad I am German
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Suppose a species of bird called the red-crested warbler has a plumage length that is controlled by a single gene. The Plm allel
AleksAgata [21]

We are going to have different allele frequencies for the two populations

North American:

72 birds total => 144 alleles

72 - 55 birds = 17 short plume birds.

q^2 = (2*17) / 114 = 0.236

Freq(short plume allele) = q = 0.486

Freq(long plume allele) = p = 1 - q = 0.514

From this North American population we get

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds total => 504 alleles

252 - 75 birds = 177 short plume birds.

q^2 = (2*177) / 504 = 0.702

Freq(short plume allele) = q = 0.838

Freq(long plume allele) = p = 1 - q = 0.162

From this South American population we get

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

Blended population has

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population has the p and q from the blended population. The new population has 1000 individuals. The portion of long plumed will be homozygote long plumage + heterozygote, which is p^2 + 2pq, and you multiply that by the population size 1000 to get the final answer.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (answer)

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Answer:

tbh i think it 6

Explanation:

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Tge cell membrane it does the function of the car's body
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