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kodGreya [7K]
3 years ago
7

Arrange the steps in the correct order to perform this subtraction problem.

Mathematics
2 answers:
koban [17]3 years ago
6 0

(103*102*1.1)-4.9 or at least that is the order I would do it in. The answer to the problem is11551.7 if you need it. :)

Tema [17]3 years ago
5 0

<u>Answer with step-by-step explanation:</u>

We are given the following expression and we are to arrange the steps in the correct order to perform this subtraction problem:

1.1 × 103 – 4.9 × 102

We will solve this according to the standard order of operations to solve an expression.

So we will first do the multiplications to get:

(1.1 × 103) – (4.9 × 102)

113.3 - 499.8

And now we will do the subtraction to get:

-386.5

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6x^2-48x-29

Step-by-step explanation:

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1. if the bearing of p from y is 048° what is the bearing of y from p .
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See below and image

Step-by-step explanation:

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5 0
2 years ago
8. Misty created the number pattern below. 32, 28, 24, 20, ... If n represents a number in this pattern, which rule could be use
geniusboy [140]

Answer:

An = 32 - (4*(n-1))

Step-by-step explanation:

the starting term for this pattern is 32 (which you will need to include in the "rule")

you also know that the next term is the previous term - 4

so!

we can write this pattern as

An = 32 - (4*(n-1))

An = any number of term in the pattern

- ex). A2 = 28, A3 = 24, etc

n = the nth term

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4 0
3 years ago
1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the
Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

f(x)=e^{3x}+\cos(5x),

g(x)=e^{3x}-\cos(5x),

h(x)=\cos(5x).

Then, letting α = 1, β= -1 and ω = -2, we see that:

\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0
3 years ago
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