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2 years ago

Arrange the steps in the correct order to perform this subtraction problem.

2 answers:

6 0

(103*102*1.1)-4.9 or at least that is the order I would do it in. The answer to the problem is11551.7 if you need it. :)

Tema [17]2 years ago

5 0

<u>Answer with step-by-step explanation:</u>

We are given the following expression and we are to arrange the steps in the correct order to perform this subtraction problem:

1.1 × 103 – 4.9 × 102

We will solve this according to the standard order of operations to solve an expression.

So we will first do the multiplications to get:

(1.1 × 103) – (4.9 × 102)

113.3 - 499.8

And now we will do the subtraction to get:

-386.5

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What is the volume of a sphere if it has a radius of 3 centimeters? (Use 3.14 for TT.)

snow_tiger [21]

Answer:

9.52

Step-by-step explanation:

4 0

2 years ago

What is the value of f(-4)

nirvana33 [79]

4 is what is knows as the factorial of 4. 4=4*3*2*1=24

8 0

3 years ago

Factor

solmaris [256]

The correct answer is C) (5m^50 - 11n^8) (5m^50 + 11n^8)

We can tell this because of the rule regarding factoring the difference of two perfect squares. When we have two squares being multiplied, we can use the following rule.

a^2 - b^2 = (a - b)(a + b)

In this case, or first term is 25m^100. So we can solve that by setting it equal to a^2.

a^2 = 25m^100 -----> take the square root of both sides

a = 5m^50

Then we can do the same for the b term.

b^2 = 121n^16 ----->take the square root of both sides

b = 11n^8

Now we can use both in the equation already given

(a - b)(a + b)

(5m^50 - 11n^16)(5m^50 + 11n^16)

8 0

2 years ago

Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3

nlexa [21]

Answer:

$(x,y) = (5,-6)$

Step-by-step explanation:

$\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\$

$~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)$

$\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\$

$\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5$

$y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6$

$\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)$

7 0

1 year ago

Are these easyyyyyyyyyyyyyyyyyyyyyyyy

mixer [17]

Answer:

Step-by-step explanation:

no they are not they are hard

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2 years ago