2Ag +(aq) + SO4 2-(aq)------>Ag2SO4 (s)
I honestly don’t know the answer to this one
Answer:
The given sample is aluminum.
Explanation:
Given data:
Mass of unknown sample = 54 g
Volume of given sample = 20cm³
Is sample is Al = ?
Solution:
In order to solve this problem we must know the density of Al from literature.
density of Al = 2.7 g/cm³
Now we will calculate the density of given unknown sample.
d = m/v
d = 54 g/ 20cm³
d = 2.7 g/cm³
Thus given sample is aluminum.
Answer:
In fluorine, the electrons are tightly held to the nuclei. The electrons have little chance to wander to one side of the molecule, so the London dispersion forces are relatively weak. At a low enough temperature the molecules will all be solids. At a high enough temperature they will all be gases.