•3.9g of ammonia
•molar mass of ammonia = 17.03g/mol
1st you have to covert grams to moles by dividing the mass of ammonia with the molar mass:
(3.9 g)/ (17.03g/mol) = 0.22900763mols
Then convert the moles to molecules by multiplying it with Avogadro’s number:
Avogadro’s number: 6.022 x 10^23
0.22900763mols x (6.022 x 10^23 molecs/mol)
= 1.38 x 10^23 molecules
Answer:
Using cobalt glass could be helpful to identify elements that weakly emit blue and/or violet.
Explanation:
Answer:
0.05 mol
Explanation:
The balanced equation for the reaction that takes place is:
- 2C₂H₂ (g) + 5O₂ (g) → 4CO₂ (g) + 2H₂O (g)
Now we<u> convert 0.10 moles of carbon dioxide (CO₂) into moles of acetylene (C₂H₂)</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 0.10 mol CO₂ *
= 0.05 mol C₂H₂