The structure of Methanol (CH₃OH) is shown below. This structure contains
2 lone pair of electrons on oxygen (highlighted red). Electronic configuration of oxygen is,
Oxygen = 8 = 1s², 2s², 2px², 2py¹, 2pz¹
There are six electrons in valence shell of oxygen, among these six electrons two electrons are unpaired and involved in forming covalent bond with hydrogen and carbon, while remaining 4 electrons in pair (i.e. 2s², 2px²) exists as lone pairs.
Answer:

Explanation:
N2(g)+O2(g)⇌2NO(g), 
N2(g)+2H2(g)⇌N2H4(g), 
2H2O(g)⇌2H2(g)+O2(g), 
If we add above reaction we will get:
2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g) Eq (1)
Equilibrium constant for Eq (1) is 
Divide Eq (1) by 2, it will become:
N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g) Eq (2)
Equilibrium constant for Eq (2) is 

In general, if a reaction is spontaneous, the reactants possess more free energy than the products.
<u>TRUE </u>
FALSE
It was disproved by the discovery of the electrons
The answer is <span>B. nonpolar.
Polar molecules dissolve best in polar solvents while nonpolar molecules dissolve best in nonpolar solvents. </span>Oils are nonpolar. So, they will dissolve best in nonpolar solvents. If you put oil in some polar solvent, such as water, it will hardly dissolve.