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lianna [129]
3 years ago
14

Describe in three sentences how Ca (Calcium) can get a positive two charge?

Chemistry
1 answer:
Pavel [41]3 years ago
4 0
Calcium will want to lose two electrons to have a stable electron configuration of a Noble Gas, Argon. When it loses its two electron, calcium (20 protons = + charge) will have only 18 electrons (- charge); thus will have a 2+ charge
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Compounds mixtures and elements ​
Jlenok [28]

Compound - made out of two or more types of elements chemically combined

Mixture - two or more substances in which the substances retain their identity

Element - simplest form of matter that is present by itself

8 0
4 years ago
You have an unknown gas. When a glowing splint is placed in it, the splint goes out. Which gas (oxygen, carbon dioxide, or hydro
maksim [4K]

Hydrogen

Hydrogen is identified by the glowing splint described in the question.

3 0
4 years ago
Predict (to 3 sig figs) the isochoric specific heat of gaseous SF6 (molar mass 146.06 g/mol) at 1200 K, assuming that at this te
bazaltina [42]

Explanation:

As it is known that SF_{6} molecule is a non-linear molecule. Therefore, its isochoric heat capacity will be as follows.

              C_{v} = \frac{3}{2}R + \frac{3}{2}R + (3 \times 7 - 6)R

                         = \frac{3}{2}R + \frac{3}{2}R + 15R

                         = 18 R

Also,    C_{V} = M \times C_{v}

where,     C_{V} = molar heat capacity

                    M = molecular mass

               C_{v} = specific heat

Hence, calculate the value of C_{v} as follows.

                 C_{V} = M \times C_{v}

               8 \times 8.314 \times 10^{7} = 146.06 \times C_{v}

               C_{v} = 10.2 \times 10^{6} erg. K^{-1}. gm^{-1}

This means that value of isochoric specific heat is 10.2 \times 10^{6} erg. K^{-1}. gm^{-1}.

Yes, we have to assume ideal gas behavior because for ideal gas:

                         dU = nC_{v}dT

Whereas for real gases "\frac{an^{2}}{V^{2}}" has to be added here.

5 0
3 years ago
1. Es un
artcher [175]

Answer:

A ) MOVIMIENTO

Explanation:

PLEASE MARK ME AS BRAINLIEST

7 0
3 years ago
Read 2 more answers
When the pressure that a gas exerts
Savatey [412]
<h2>Hello!</h2>

The answer is:

When the pressure that a gas exerts  on a sealed container changes from

22.5 psi to 19.86 psi, the  temperature changes from 110°C to

65.9°C.

<h2>Why?</h2>

To calculate which is the last pressure, we need to use Gay-Lussac's law.

The Gay-Lussac's Law states that when the volume is kept constant, the temperature (absolute temperature) and the pressure are proportional.

The Gay-Lussac's equation states that:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

We are given the following information:

We need to remember that since the temperatures are given in Celsius degrees, we need to convert it to Kelvin (absolute temperature) before use the equation, so:

P_1=22.5Psi\\T_1=110\°C=110\°C+273.15=383.15K\\T_1=65.9\°C=65\°C+273.15=338.15K

Now, calculating we have:

\frac{P_1}{T_1}*(T_2)=P_2\\\\P_2=\frac{P_1}{T_1}*(T_2)=\frac{22.5Psi}{383.15}*338.15=19.86Psi

Hence, the final pressure is equal to 19.86 Psi.

Have a nice day!

8 0
3 years ago
Read 2 more answers
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