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3 years ago

Pls help number 7 I need helpll

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

7 0

Answer:

The least common multiple is the smallest

Step-by-step explanation:

It is easy. Net time you can find math help on khan Academy.

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A polynomlal has been factored, as SHOWI Deluw.

Tom [10]

Answer:

The zeros are 6,-5,9

Step-by-step explanation:

The factored form of the polynomial is given as:

$f(x) = (x - 6)(x + 5)(x - 9)$

To find the zeros of this function, we set f(x)=0 and solve for x.

$(x - 6)(x + 5)(x - 9) = 0$

This implies that:

$(x - 6) = 0 \: or \: (x + 5) = 0 \: or \: (x - 9) = 0$

We solve for x to get:

$x = 6 \: or \: x = - 5 \: or \: x = 9$

The zeros are 6,-5,9

3 0

3 years ago

Craig is designing a new cylinder-shaped can for a pet food company. He wants the height of the can to be 40 mm and the radius o

devlian [24]

The height of the can for this case is given by:
h = 40 mm
The radius of the can is given by:
r = (1 3/8) * h
Substituting values:
r = (1 3/8) * 40
r = 55 mm
Therefore, the diameter of the can is:
d = 2 * r
d = 2 * 55
d = 110 mm
Answer:
The diameter of the can will be:
d = 110 mm

3 0

3 years ago

Solve for 3.3x-4=-13.9

evablogger [386]

Answer: Simple and best practice solution for 3.3x-4=-13.9 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

Step-by-step explanation: Idk how to explain I’m just smart so I can figure it out

4 0

3 years ago

Read 2 more answers

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is