vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.
Givens
vi = 160 ft/s
vf = 0 (the rocket stops at the maximum height.)
a = - 9.81 m/s
t = ????
Remark
YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.
Equation
a = (vf - vi)/t
Solve
- 32 = (0 - 160)/t Multiply both sides by t
-32 * t = - 160 Divide by -32
t = - 160/-32
t = 5
You will also need to solve for the height to answer part B
t = 5
vi = 160 m/s
a = - 32
d = ???
d = vi*t + 1/2 a t^2
d = 160*5 + 1/2 * - 32 * 5^2
d = 800 - 400
d = 400 feet
Part B
You are at the maximum height. vi is 0 this time because you are starting to descend.
vi = 0
a = 32 m/s^2
d = 400 feet
t = ??
formula
d = vi*t + 1/2 a t^2
400 = 0 + 1/2 * 32 * t^2
400 = 16 * t^2
400/16 = t^2
t^2 = 25
t = 5 sec
The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.
Answer:
93.75 Kg
Step-by-step explanation:
Farmer spreads 25 kg fertilizer over an area of 4000 m square .
So, Over 1 m square ,
kg of fertilizer will be needed
As we know , 1 hectare = 10,000 m square.
So, 1.5 hectare equals 15,000 m square.
So, for 15,000 m square , Fertilizer needed will be equal to
×15,000 = 93.75 Kg
So, 93.75 Kg of fertilizer is needed for 1.5 ha of land.
Tossing a coin would be 1/2 because a coin has two sides and it has 1 out of two sides to land on the side you want it to land on. So that answer is 1/2. The dice rolling on an even number on a six-sided number cube would be 3/6. Which if you simplify it, it would be 1/2. The answer to both of them is 1/2!
You did everything correctly! I did it myself...all of your subtraction is correct, then I added the answers together and I got 51. Where you trying to get another answer?
Answer:
The distance of ship B from the Harbor is 32.26 miles
Step-by-step explanation:
Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.
I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

.... flip both fractions.
.... multiply both sides by 22


So the distance of ship B from the Harbor is 32.26 miles
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